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4 years ago

12

Which alternative energy source would be expected to be the least dependent upon the weather?

2 answers:

Ivahew [28]4 years ago

6 0

Answer: c. geothermal power

Geothermal energy is expected to be the least dependent upon the weather conditions. It is a renewable source of energy liberated in the form of water springs. The water in the geosphere being heated by the heat liberated from the hot magma in the mantle. The hot water liberated is used as a source of thermal power. As, the geothermal power liberates from the earth crust it is not affected by the external environmental conditions including weather.

Elza [17]4 years ago

3 0

Of the three sources listed, geothermal energy
is the least dependent on the weather.
(Once it's installed and running, that is.)

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3 years ago

A mixture of 0.439 M H 2 , 0.317 M I 2 , and 0.877 M HI is enclosed in a vessel and heated to 430 °C. H 2 ( g ) + I 2 ( g ) − ⇀

n200080 [17]

Answer : The concentration of $H_2,I_2\text{ and }HI$ at equilibrium is, 0.244 M, 0.122 M and 1.267 M respectively.

Explanation :

The given chemical reaction is:

$H_2(g)+I_2(g)\rightarrow 2HI(g)$

Initial conc. 0.439 0.317 0.877

At eqm. (0.439-x) (0.317-x) (0.877+2x)

As we are given:

$K_c=54.3$

The expression for equilibrium constant is:

$K=\frac{[HI]^2}{[H_2][I_2]}$

Now put all the given values in this expression, we get:

$54.3=\frac{(0.877+2x)^2}{(0.439-x)\times (0.317-x)}$

x = 0.195 and x = 0.690

We are neglecting the value of x = 0.690 because equilibrium concentration can not be more than initial concentration.

Thus, the value of x = 0.195 M

The concentration of $H_2$ at equilibrium = (0.439-x) = (0.439-0.195) = 0.244 M

The concentration of $I_2$ at equilibrium = (0.317-x) = (0.317-0.195) = 0.122 M

The concentration of $HI$ at equilibrium = (0.877+2x) = (0.877+2\times 0.195) = 1.267 M

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3 years ago