All categories

3 years ago

Which alternative energy source would be expected to be the least dependent upon the weather?

Chemistry

2 answers:

Ivahew [28]3 years ago

6 0

Answer: c. geothermal power

Geothermal energy is expected to be the least dependent upon the weather conditions. It is a renewable source of energy liberated in the form of water springs. The water in the geosphere being heated by the heat liberated from the hot magma in the mantle. The hot water liberated is used as a source of thermal power. As, the geothermal power liberates from the earth crust it is not affected by the external environmental conditions including weather.

Elza [17]3 years ago

3 0

Of the three sources listed, geothermal energy
is the least dependent on the weather.
(Once it's installed and running, that is.)

You might be interested in

A mixture of 10 cm3 of methane and 10 cm3 of ethane was sparked with an excess of oxygen. After cooling to room temperature, thr

Tpy6a [65]

In the combustion process using excess oxygen, each mole of methane results to 1 mole of co2 while ethane produces 2 moles of Co2. Under same conditions, these can be translated to volume. Hence the total volume absorbed is 10 cm3 + 20 cm3 = 30 cm3.

5 0

3 years ago

_Fe2O3+ ___C --> __Fe + ___CO2

aev [14]

Answer:

2, 3, 4, 3

Explanation:

this is the answer

4 0

3 years ago

Cells get energy from food to sustain the life of the organism.

Sati [7]

The answer is B hope this helped

4 0

3 years ago

Read 2 more answers

The reaction is proceeding at a rate of 0.0080 Ms-1 in 50.0 mL of solution in a system with unknown concentrations of A and B. W

Leokris [45]

Answer:

0.0010 mol·L⁻¹s⁻¹

Explanation:

Assume the rate law is

rate = k[A][B]²

If you are comparing two rates,

$\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \dfrac{k_{2}\text{[A]}_2[\text{B]}_{2}^{2}}{k_{1}\text{[A]}_1[\text{B]}_{1}^{2}}= \left (\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}}\right ) \left (\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}\right )^{2}$

You are cutting each concentration in half, so

$\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}} = \dfrac{1}{2}\text{ and }\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}= \dfrac{1}{2}$

Then,

$\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \left (\dfrac{1}{2}\right ) \left (\dfrac{1}{2}\right )^{2} = \dfrac{1}{2}\times\dfrac{1}{4} = \dfrac{1}{8}\\\\\text{rate}_{2} = \dfrac{1}{8}\times \text{rate}_{1}= \dfrac{1}{8}\times \text{0.0080 mol$\cdot$L$^{-1}$s$^{-1}$} = \textbf{0.0010 mol$\cdot$L$^{-1}$s$^{-1}$}\\\\\text{The new rate is $\large \boxed{\textbf{0.0010 mol$\cdot$L$^\mathbf{{-1}}$s$^{\mathbf{-1}}$}}$}$

8 0

3 years ago

Express the rate of the reaction in terms of the change in concentration of each of the reactants and products.

weeeeeb [17]

Answer:

c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$2HBr(g)\rightarrow H_2(g)+Br_2(g)$

Thus, the rate is given as:

$rate=-\frac{1}{2} \frac{\Delta [HBr]}{\Delta t}=\frac{\Delta [Br_2]}{\Delta t} =\frac{\Delta [H_2]}{\Delta t}$

It is necessary to remember that each concentration to time interval is divided into the stoichiometric coefficient, that is why HBr has a 1/2. Moreover, the concentration HBr is negative since it is a reactant and it has a negative rate due to its consumption.

Therefore, the answer is:

c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt

Best regards.

4 0

3 years ago