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Volgvan
1 year ago
7

A hydrocarbon is a compound that contains mostly carbon and hydrogen. Calculate the percent composition (by mass) of the followi

ng hydrocarbon: c9h20.
Chemistry
1 answer:
nata0808 [166]1 year ago
3 0

The percentages of carbon and hydrogen 84.37%  and 15.693% respectively.

<h3>What is a molar mass ?</h3>

The mass of a certain chemical element or chemical compound (g) divided by the amount of material is known as the molar mass (mol). By multiplying the standard atomic masses (in g/mol) of the component atoms, one may get the molar mass of a compound.

Molar mass of the compound is the mass of 1 mole of compound which is the sum of masses of each element.

C_9H_{20.

Mass of 1 mole of compound= mass of carbon + mass of hydrogen+ = 9(12) + 20(1)= 128 g.

Percentage by mass of carbon = \frac{mass \ of \ the \ carbon}{mass \ of \ the\  molecule }%

= 108/128 * 100

= 84.37 %

Percentage by mass of carbon = \frac{mass \ of \ the \ H}{mass \ of \ the\  molecule } %

=20/128 *100 =15.63 %

The percentages of carbon and hydrogen 84.37%  and 15.693% respectively.

To learn more about Molar mass  refer,

brainly.com/question/837939

#SPJ4

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Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
zaharov [31]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

  • V = 2.4 L = 0.0024
  • P = 86126.25 Pa
  • T =  287 K
  • m = 0.622
  • R = 8.314

The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass =  7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

More about the ideal gas equation link is given below.

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