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Volgvan
1 year ago
7

A hydrocarbon is a compound that contains mostly carbon and hydrogen. Calculate the percent composition (by mass) of the followi

ng hydrocarbon: c9h20.
Chemistry
1 answer:
nata0808 [166]1 year ago
3 0

The percentages of carbon and hydrogen 84.37%  and 15.693% respectively.

<h3>What is a molar mass ?</h3>

The mass of a certain chemical element or chemical compound (g) divided by the amount of material is known as the molar mass (mol). By multiplying the standard atomic masses (in g/mol) of the component atoms, one may get the molar mass of a compound.

Molar mass of the compound is the mass of 1 mole of compound which is the sum of masses of each element.

C_9H_{20.

Mass of 1 mole of compound= mass of carbon + mass of hydrogen+ = 9(12) + 20(1)= 128 g.

Percentage by mass of carbon = \frac{mass \ of \ the \ carbon}{mass \ of \ the\  molecule }%

= 108/128 * 100

= 84.37 %

Percentage by mass of carbon = \frac{mass \ of \ the \ H}{mass \ of \ the\  molecule } %

=20/128 *100 =15.63 %

The percentages of carbon and hydrogen 84.37%  and 15.693% respectively.

To learn more about Molar mass  refer,

brainly.com/question/837939

#SPJ4

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Calculate the volume in liters of a barium acetate solution that contains of barium acetate . Be sure your answer has the correc
Ilya [14]

Answer:

1.09 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:

100 g × (1 mol/255.43 g) = 0.391 mol

0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:

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5 0
3 years ago
Read 2 more answers
A 25.00 ml sample of h3po4 solution is neutralized by exactly 54.93 ml of 0.04345 m ca(oh)2. what is the molarity of the h3po4 s
son4ous [18]
The neutralization equation is:
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From this equation we can see that 3 moles of Ca(OH)₂ react with 2 moles of H₃PO₄

Numbers of mmol of Ca(OH)₂ = M x V = 0.04345 x 54.93 = 2.387 mmol

Number of mmol of H₃PO₄ = 2.387 x (2/3) = 1.591 mmol

Molarity of solution = n (mmol) / V(ml) = 1.591 / 25 = 0.0636 M
8 0
3 years ago
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Determine the correct set-up below to determine what mass, in grams, of N2 is needed to completely react with 105 g F2 ?
neonofarm [45]

Answer:

C: 1 mol F2/38 g F2

Explanation:

The reaction equation is;

N2 + 3F2 = 2NF3

Now, to know how many grams, of N2 is needed to completely react with 105 g F2 and since the molar mass of N2 is 28.02 g/mol, Molar mass of F2 is 38 g/mol, number of moles attached to N2 and F2 in the reaction are 1 and 3 moles respectively, then we will have;

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Option C is Thus correct

4 0
3 years ago
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