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Volgvan
1 year ago
7

A hydrocarbon is a compound that contains mostly carbon and hydrogen. Calculate the percent composition (by mass) of the followi

ng hydrocarbon: c9h20.
Chemistry
1 answer:
nata0808 [166]1 year ago
3 0

The percentages of carbon and hydrogen 84.37%  and 15.693% respectively.

<h3>What is a molar mass ?</h3>

The mass of a certain chemical element or chemical compound (g) divided by the amount of material is known as the molar mass (mol). By multiplying the standard atomic masses (in g/mol) of the component atoms, one may get the molar mass of a compound.

Molar mass of the compound is the mass of 1 mole of compound which is the sum of masses of each element.

C_9H_{20.

Mass of 1 mole of compound= mass of carbon + mass of hydrogen+ = 9(12) + 20(1)= 128 g.

Percentage by mass of carbon = \frac{mass \ of \ the \ carbon}{mass \ of \ the\  molecule }%

= 108/128 * 100

= 84.37 %

Percentage by mass of carbon = \frac{mass \ of \ the \ H}{mass \ of \ the\  molecule } %

=20/128 *100 =15.63 %

The percentages of carbon and hydrogen 84.37%  and 15.693% respectively.

To learn more about Molar mass  refer,

brainly.com/question/837939

#SPJ4

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Answer:

\boxed {\boxed {\sf 232.9 \textdegree C}}

Explanation:

This question asks us to find the temperature change given a volume change. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:

\frac {V_1}{T_1}= \frac{V_2}{T_2}

The volume of the gas starts at 250 milliliters and the temperature is 137 °C.

\frac{250 \ mL}{137 \textdegree C}= \frac{V_2}{T_2}

The volume of the gas is increased to 425 milliliters, but the temperature is unknown.

\frac{250 \ mL}{137 \textdegree C}= \frac{425 \ mL}{T_2}

We are solving for the new temperature, so we must isolate the variable T₂. First, cross multiply. Multiply the first numerator and second denominator, then multiply the first denominator and second numerator.

250 \ mL * T_2 = 137 \textdegree C * 425 \ mL

Now the variable is being multiplied by 250 milliliters. The inverse of multiplication is division. Divide both sides of the equation by 250 mL.

\frac{250 \ mL * T_2}{250 \ mL}=\frac{ 137 \textdegree C * 425 \ mL}{250 \ mL}

T_2=\frac{ 137 \textdegree C * 425 \ mL}{250 \ mL}

The units of milliliters (mL) cancel.

T_2=\frac{ 137 \textdegree C * 425 }{250 }

T_2= \frac{58225}{250} \textdegree C

T_2=232.9 \textdegree C

The temperature changes to <u>232.9 degrees Celsius.</u>

3 0
3 years ago
What is the name for CH3-CH2-CH2-O-CH2-CH3?
BabaBlast [244]

Answer:

idk maybe chlorine 12

Explanation:

6 0
3 years ago
Calculate the number of atoms of sodium in a 4.5-gram sample
allochka39001 [22]

Answer:

1.18×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms.

From the above concept, 1 mole of sodium also contains 6.02×10²³ atoms.

1 mole of sodium = 23 g.

Thus,

23 g of sodium contains 6.02×10²³ atoms.

Therefore, 4.5 g of sodium will contain = (4.5 × 6.02×10²³)/23 = 1.18×10²³ atoms.

From the above calculation,

4.5 g of sodium contains 1.18×10²³ atoms.

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3 years ago
Ch2(c(ch3) 2 iupac name​
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Answer:

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5 0
3 years ago
Converting the following mm Hg (torr) to standard
11Alexandr11 [23.1K]

Explanation:

Given:

20.5 torr

78.6 torr

225 torr

Change into atm

Computation:

We know that;

1 torr = 0.00131579 atm

So,

1. 20.5 torr

= 20.5 x 0.00131579 atm

= 0.02697

= 0.027 atm (Approx)

2. 78.6 torr

= 78.6 x 0.00131579 atm

= 0.103090

= 0.103 atm (Approx)

3. 225 torr

= 225 x 0.00131579 atm

= 0.2960

= 0.296 atm (Approx)

5 0
3 years ago
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