Answer:
Explanation:
The first attached diagram shows the proposed phenol that is being treated with KOH to form Oxonine (CₐHₐO).
Reaction of Arylhalide after treatment with KOH lead to the displacement of Bromine atom with the hydrogen from the hydroxyl (OH) substituent , then forming HBr , leaving the oxy (-O) atom alone to form an Oxonine compound.
Therefore the propose structure for the product (Oxonine) CₐHₐO is shown in the second diagram attached below.
Wax and Oxygen. The CO2 and H2O would be the products :)
Hydrogen is a non-polar gas with very weak intermolecular forces of attraction. Hydrogen will deviate from the ideal gas behavior at high pressure.
C- K4O8 and K2O4
K4O8/4 =KO2
K2O4/2 =KO2