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IceJOKER [234]
3 years ago
7

What is the identity of a sample that has a mass of 100.5 g and a volume of 7.42 cm3?

Chemistry
2 answers:
ElenaW [278]3 years ago
5 0
The answer will be mercury
yawa3891 [41]3 years ago
3 0

<u>Answer:</u> The correct answer is Option 4.

<u>Explanation:</u>

To calculate volume of a substance, we use the equation:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

Mass of sample = 100.5 g

Volume of sample = 7.42cm^3

Putting values in above equation, we get:

\text{Density of sample}=\frac{100.5g}{7.42cm^3}\\\\\text{Density of sample}=13.6g/cm^3

The known density of the given metals are:

Density of lead = 11.34g/cm^3

Density of iron = 7.87g/cm^3

Density of gold = 19.32g/cm^3

Density of mercury = 13.6g/cm^3

The calculated density matches the given density of mercury.

Hence, the correct answer is Option 4.

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526 L O2 x 1 mol O2 / 22.4 L = 23.5 mol O2
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8 0
2 years ago
A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL
ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

6 0
3 years ago
Which atoms in the amino acids become the h2o molecule produced by their action in model?
Mariana [72]

Atoms in the amino acids become the h₂O molecule produced by their action in the model and come off from the central carbon and nitrogen but not from the carboxyl, R side chain, or amine.

An amino acid is a group of organic molecules that consist of a basic acidic carboxyl group (―COOH), amino group (―NH2), and an organic R group (or side chain) that is different from each amino acid. Amino acid, the term is a short form of α-amino [alpha-amino] carboxylic acid.

Whereas, the peptide bond is the chemical bond which is a chemical bond formed between two molecules when the carboxyl group of a particular molecule reacts with the amino group of the other molecule, leading to releasing a molecule of water (H2O).

Each molecule consists of a central carbon atom referred to as the α-carbon, to which both a carboxyl group and amino are attached. The remaining two bonds of the α-carbon atom are generally occupied  by  the R group and a hydrogen (H) atom .

To know more about amino acids refer to the link brainly.com/question/14583479?referrer=searchResults.

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4 0
1 year ago
If 9.6 X 1021 molecules of hydrogen are reacted with excess nitrogen, how many liters of ammonia can be produced at STP?
diamong [38]

The volume of NH₃ produced at STP : 0.237 L

<h3>Further explanation</h3>

Reaction

N₂ + 3H₂ → 2NH₃

1 mol = 6.02 x 10²³ particles

9.6 X 10²¹ molecules of Hydrogen, mol :

\tt \dfrac{9.61\times 10^{21}}{6.02\times 10^{23}}=1.596\times 10^{-2}~moles

mol H₂ : mol NH₃ = 3 : 2

mol NH₃ :

\tt \dfrac{2}{3}\times 1.596\times 10^{-2}=0.0106

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). <em>At STP, Vm is 22.4 liters/mol.</em>

The volume of NH₃ :

\tt 0.0106\times 22.4=0.237~L

<em />

8 0
2 years ago
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