Answer:1) 100 gm mass should be placed at 95 cm mark.
2) Mass of 112.5 gm should be placed at 90 cm mark.
Explanation:
For equilibrium of the meter stick the sum of the moment's generated by the masses should be equal and opposite
Answer to part b)
Since a meter stick is 100 cm long and it is pivoted at it's center i.e at 50 cm
Thus
1) Moment generated by 100 gm mass about center = 
Let a mass 'm' be placed at 90 cm mark thus moment it generates equals
Equating both the moments we get
Answer to part a)
Let the 100 grams weight be placed at a distance 'x' right of center
Moment generated by 100 grams weight equals
equating the moments of the forces we get
thus the mass of 100 gm should be placed at 95 cm mark in the scale.
In order to find the speed per minute you will have to divide the two numbers together. You need to do 36/5.4 so the answer will be around 6.7 feet per minute.
Answer:
Fx = 32.14 [N]
Fy = 38.3 [N]
Explanation:
To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.
F = 50 [N]
Fx = 50*cos(50) = 32.14 [N]
Fy = 50*sin(50) = 38.3 [N]
We can verify this result using the Pythagorean theorem.
![F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N]](https://tex.z-dn.net/?f=F%20%3D%20%5Csqrt%7B%2832.14%29%5E%7B2%7D%2B%20%2838.3%29%5E%7B2%7D%7D%20%5C%5CF%20%3D%2050%20%5BN%5D)
The wavelength of the golf ball is <u>2.328×10⁻³⁴m.</u>
All moving particles with mass have a matter wave associated with it. These matter waves are called deBroglie waves.
The deBroglie wavelength λ of a particle is given by,
Here, h is the Planck's constant, m is the mass of the ball and v is its velocity.
Calculate the deBroglie wavelength of the moving golf ball by substituting 6.626×10⁻³⁴J s for h, 45.9×10⁻³kg for m and 62.0 m/s for v.
The wavelength of the golf ball is <u>2.328×10⁻³⁴m.</u>
