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nekit [7.7K]
3 years ago
10

A force of 50n is applied to an object at an angle of 50 degrees measured relative to the horizontal. Determine the horizontal a

nd vertical components of the applied force?
Physics
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:

Fx = 32.14 [N]

Fy  = 38.3 [N]

Explanation:

To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.

F = 50 [N]

Fx = 50*cos(50) = 32.14 [N]

Fy = 50*sin(50) = 38.3 [N]

We can verify this result using the Pythagorean theorem.

F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N]

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is set into oscillatory motion with an amplitude of 23.195 cm on a spring with a spring constant of 15.2676 N/m. The mass of the
fredd [130]

Answer:

maximum speed of the bananas is 18.8183 m/s

Explanation:

Given data

amplitude A =  23.195 cm

spring constant K = 15.2676 N/m

mass of the bananas m = 56.9816 kg

to find out

maximum speed of the bananas

solution

we know that radial oscillation frequency formula that is = √(K/A)

radial oscillation frequency = √(15.2676/23.195)

radial oscillation frequency is 0.8113125 rad/s

so maximum speed of the bananas = radial oscillation frequency × amplitude

maximum speed of the bananas = 0.8113125 × 23.195

maximum speed of the bananas is 18.8183 m/s

8 0
3 years ago
A uniform wooden plank with a mass of 75kg and length of 5m is placed on top of a brick wall so that 1.5m of plank extends beyon
jek_recluse [69]

Answer:

x₂ = 1.33 m

Explanation:

For this exercise we must use the rotational equilibrium condition, where the counterclockwise rotations are positive and the zero of the reference system is placed at the turning point on the wall

            Στ = 0

            W₁ x₁ - W₂ x₂ = 0

where W₁ is the weight of the woman, W₂ the weight of the table.

Let's find the distances.

Since the table is homogeneous, its center of mass coincides with its geometric center, measured at zero.

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The distance of the person is x₂ measured from the turning point, at the point where the board begins to turn the girl must be on the left side so her torque must be negative

            x₂ = \frac{M_1g  }{m_2 g} \ x_1

           

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7 0
3 years ago
Frame S' passes frame S in the usual way (positive directions). An object also moves in the positive direction. Which is true? T
lisov135 [29]

Answer:

The answer is "The object's speed relative to S can be greater than or less than its speed relative to S', depending on the actual values."

Explanation:

The S' frame and the object are moving in a positive direction. The object is moving with respect to the S frame so the S frame the rest frame

take the velocity of the object with respect to the rest frame as v and the velocity of the S' frame with respect S frame as v2

relative velocity of the object to the S' frame would be

Vrel = v2- v

This means the Vrel of the object with respect to the S' frame is less than the Vrel  of the object with respect to the S frame

However is the S' velocity is greater than that of the object then the Vrel of the object with respect to the S' frame is greater than the Vrel of the object with respect to the S frame.

This would mean the second option is the answer, the relative speed of the object depends on the actual values.

3 0
3 years ago
I WILL GET BRAINLIEST PLS HELP A student attempts to push a box across the floor. The student decides to create a free-body diag
MissTica

Answer: The gravitational

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Genes are found on DNA, which makes up chromosomes in the nucleus of a cell. True False
zheka24 [161]
The sentence is accurate, therefore TRUE is the answer.
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