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nekit [7.7K]
3 years ago
10

A force of 50n is applied to an object at an angle of 50 degrees measured relative to the horizontal. Determine the horizontal a

nd vertical components of the applied force?
Physics
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:

Fx = 32.14 [N]

Fy  = 38.3 [N]

Explanation:

To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.

F = 50 [N]

Fx = 50*cos(50) = 32.14 [N]

Fy = 50*sin(50) = 38.3 [N]

We can verify this result using the Pythagorean theorem.

F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N]

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