Answer:
W = 21409.2 J
Explanation:
Given,
The mass of the woman, m = 77 Kg
The length of the water slide, S = 42.6 m
The inclination of the water slide, ∅ = 42.3
The constant velocity of the women sliding, 20.3 m/s
The kinetic friction of the sliding force is given by the formula
Fₓ = μₓ η
Where,
μₓ - coefficient of kinetic friction
η - normal force acting on the body
Since the water slide is inclined at an angle and the person is sliding with constant velocity. The coefficient of friction becomes,
μₓ = tan∅
And, η = mg cos∅
Therefore, the kinetic friction force becomes
Fₓ = tan∅ mg cos∅
Substituting the given values in the above equation
Fₓ = 0.9 x 77 x 9.8 x 0,74
= 502.56 N
The work done by the kinetic friction on the person
W = Fₓ · S
= 502.56 N x 42.6 m
= 21409.2 J
Hence, the work done by the friction on the woman is, W = 21409.2 J
