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kondaur [170]
2 years ago
15

What does this tell you about the direction and magnitude of the acceleration acting on the cannonball throughout its duration o

f flight?
Physics
1 answer:
Lyrx [107]2 years ago
3 0

Answer:

Direction remains the same but velocity changes.

Explanation:

This tell us about the direction and magnitude of the acceleration acting on the cannonball throughout its duration of flight that its direction remains the same but its magnitude of the acceleration is continuously changing. The cannonball moves in the direction in which the cannon was fired while the velocity is highest after the fire but decreases when goes higher and when it comes back to the ground so its velocity increases against so we can say that both positive and negative acceleration occurs. Positive acceleration means increase in the magnitude of velocity whereas negative acceleration means decrease in velocity.

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Explain how motion and energy are related to roller coasters, please be specific!
Fittoniya [83]
Because when an object is in motion it has kinetic energy
4 0
2 years ago
A force of 3600 N is exerted on a piston that has an area of 0.030 m2. What force is exerted on a second piston that has an area
Airida [17]
For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:
p_1 = p_2
which becomes
\frac{F_1}{A_1}= \frac{F_2}{A_2}
where
F_1=3600 N is the force on the first piston
A_1=0.030 m^2 is the area of the first piston
F_2 is the force on the second piston
A_2=0.015 m^2 is the area of the second piston

If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:
F_2=F_1  \frac{A_2}{A_1}=(3600 N) \frac{0.015 m^2}{0.030 m^2}= 1800 N
7 0
3 years ago
Read 2 more answers
A transformer has a primary coil with 375 turns of wire and a secondary coil with 1,875 turns. An AC voltage source connected ac
Sonbull [250]

Answer:

The rms voltage (in V) measured across the secondary coil is 459.62 V

Explanation:

Given;

number of turns in the primary coil, Np = 375 turns

number of turns in the secondary coil, Ns = 1875 turns

peak voltage across the primary coil, Ep = 130 V

peak voltage across the secondary coil, Es = ?

\frac{N_P}{N_s} = \frac{E_p}{E_s} \\\\E_s = \frac{N_sE_p}{N_p} \\\\E_s = \frac{1875*130}{375} \\\\E_s = 650 \ V

The rms voltage (in V) measured across the secondary coil is calculated as;

V_{rms} = \frac{V_0}{\sqrt{2} } = \frac{E_s}{\sqrt{2} } \\\\V_{rms} = \frac{650}{\sqrt{2} } = 459.62 \ V

Therefore, the rms voltage (in V) measured across the secondary coil is 459.62 V

7 0
3 years ago
A pendulum of length L=36.1 cm and mass m=168 g is released from rest when the cord makes an angle of 65.4 degrees with the vert
pychu [463]

(a) -0.211 m

At the beginning the mass is displaced such that the length of the pendulum is L = 36.1 cm and the angle with the vertical is

\theta=65.4^{\circ}

The projection of the length of the pendulum along the vertical direction is

L_y = L cos \theta = (36.1 cm)(cos 65.4^{\circ})=15.0 cm

the full length of the pendulum when the mass is at the lowest position is

L = 36.1 cm

So the y-displacement of the mass is

\Delta y = 15.0 cm - 36.1 cm = -21.1 cm = -0.211 m

(b) 0.347 J

The work done by gravity is equal to the decrease in gravitational potential energy of the mass, which is equal to

\Delta U = mg \Delta y

where we have

m = 168 g = 0.168 kg is the mass of the pendulum

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta y = 0.211 m is the vertical displacement of the pendulum

So, the work done by gravity is

W=(0.168 kg)(9.8 m/s^2)(0.211 m)=0.347 J

And the sign is positive, since the force of gravity (downward) is in the same direction as the vertical displacement of the mass.

(c) Zero

The work done by a force is:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this situation, the tension in the string always points in a radial direction (towards the pivot of the pendulum), while the displacement of the mass is tangential (it follows a circular trajectory): this means that the tension and the displacement are always perpendicular to each other, so in the formula

\theta=90^{\circ}, cos \theta = 0

and so the work done is zero.

5 0
2 years ago
Stan does 178 J of work lifting himself 0.5 m. What is Stan’s mass? The acceleration of gravity is 9.8 m/s 2 . Answer in units o
Rom4ik [11]
Work= (force)(distance)
178= m(9.81)x0.5
178=m(4.905)
178/4.905=m

His mass is 36.3 kg
4 0
3 years ago
Read 2 more answers
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