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3 years ago

Math the words in the box with the sentences below.

Physics

2 answers:

lilavasa [31]3 years ago

5 0

Answer:

1.friction

Non contract

Static force

Gravity

Tension

Spring force

Contact force

Magnetic force

Normal force

Applied force

Explanation:

Sana makatulong

Tanzania [10]3 years ago

4 0

In order of appearance on the table;

Magnetic force

Normal force

Gravity

String force

Friction

Contact force

Tension

Non Contact force

Static force

Applied force

please mark BRAINLIEST if I'm right.

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a ball is dropped from rest at a height of 45.0 m above the ground. ignore the effects of air resistance. What is the speed of c

NemiM [27]

So, the final velocity of the ball when it is 10.0 m above the ground approximately <u>26.2 m/s</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. This question uses the principle of final velocity in free fall. Free fall occurs only when an object is dropped (without initial velocity), so the falling object is only affected by the presence of gravity. In general, the final velocity in free fall can be expressed by this equation :

$\boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}}$

With the following condition :

v = final velocity (m/s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)

<h3>Problem Solving</h3>

We know that :

$\sf{h_1}$ = initial height = 45.0 m
$\sf{h_2}$ = final height = 10.0 m
g = acceleration of the gravity = 9.8 m/s²

Note :

At this point 10 m above the ground, the object can still complete its movement up to exactly 0 m above the ground.

What was asked :

v = final velocity = ... m/s

Step by Step

$\sf{v = \sqrt{2 \times g \times \Delta h}}$

$\sf{v = \sqrt{2 \times g \times (h_1 - h_2)}}$

$\sf{v = \sqrt{2 \times 9.8 \times (45 - 10)}}$

$\sf{v = \sqrt{19.6 \times 35}}$

$\sf{v = \sqrt{686}}$

$\boxed{\sf{v \approx 26.2 \: m/s}}$

<h3>Conclusion</h3>

So, the final velocity of the ball when it is 10.0 m above the ground approximately 26.2 m/s.

The relationship between acceleration and the change in velocity and time in free fall brainly.com/question/26486625

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2 years ago

A hammer strikes one end of a thick iron rail of length 8.80 m. A microphone located at the opposite end of the rail detects two

stepladder [879]

Answer:

ΔT = 0.02412 s

Explanation:

We will simply calculate the time for both the waves to travel through rail distance.

FOR THE TRAVELING THROUGH RAIL:

$T_{rail} = \frac{Distance}{Speed\ of\ Sound\ in\ Rail}\\\\T_{rail} = \frac{8.8\ m}{5950\ m/s}\\\\T_{rail} = 0.00148\ s$

FOR THE WAVE TRAVELING THROUGH AIR:

$T_{air} = \frac{Distance}{Speed\ of\ Sound\ in\ Air}\\\\T_{air} = \frac{8.8\ m}{343\ m/s}\\\\T_{air} = 0.0256\ s$

The separation in time between two pulses can now be given as follows:

$\Delta T = T_{air}-T_{rail} \\\Delta T = 0.0256\ s - 0.00148\ s\\$

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3 years ago

What are the types and properties of Carbon compounds

jarptica [38.1K]

Hardness,color,phase

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4 years ago

A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 3.50

kkurt [141]

Answer:

a) speed= 0.86m/s

b) Amplitude = 0.35m

C) Amplitude = 0.25m

Explanation: correct values in question (for the boat to travel from its highest point to its lowest, a total distance of 0.700 m . The fisherman sees that the wave crests are spaced 6.00 m apart.)

The speed of a periodic wave with wavelength and frequency is given by:

Speed = frequency × wavelength

The relation between the time period and frequency is given by:

T = 1/f

Given:

Time that the boat takes to travel from the highest point to its lowest point,t = 3.50s

Distance between the lowest point and the highest point,d = 0.70m

Wavelength = 6.0m

a) Wavelength is the distance between two successive wave crests or troughs. So, the distance between the Crest (highest point) to the next(lowest point) is a half wavelength.

The time period ,T is the time between two successive waves.

Therefore,the time it takes the boat to travel from its highest point to its lowest point is period.

T = 2 ×3.50 =7.0seconds

Frequency, f = 1/7.0

f = 0.1429Hz

Speed = frequency × wavelength

Speed = 0.1429 × 6 = 0.86m/s

b) The amplitude is the maximum magnitude of displacement from equilibrium.

Therefore, the distance between the boar's highest point to its lowest point is

Amplitude, A = distance /2

Amplitude A = 0.70/2= 0.35m

c) If the vertical distance changes to d2= 0.50m but other data remained the same, this wont change the speed of the wave because it does not depend on the vertical displacement but it will change the amplitude

A = distance /2 = 0.50m/2 = 0.25m

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3 years ago

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KonstantinChe [14]

Answer:

True

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Explanation:

Hope it helps

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3 years ago