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2 years ago

5

Rahima goes jogging on a course that is 2.75kilometers long. If she completes the full course every morning, how many kilometers

does she jog in
one week? Explain how you got your answer.

2 answers:

Arada [10]2 years ago

6 0

Answer:

<h2>19.25km</h2>

Step-by-step explanation:

Step one:

given data

we are told that the distance that Rahima covers on a daily is 2.75km long

we also know that a week has 7 days that is Mon-Sunday

Required

the total distance for a week

Step two:

Hence the total distance covered for 7 days is

=2.75*7

=19.25km

<em>Simply multiply the distance covered in a day by 7 to get the distance covered in a week </em>

BlackZzzverrR [31]2 years ago

5 0

Answer:

why would i go jogging on a course that is 2.75kilometers long. XD

Step-by-step explanation:

You might be interested in

A stadium has 50,000 seats. Seats sell for $25 in section A, $20 in section B, and $15 in section C. The number of seats in sect

Novay_Z [31]

Answers:

section A = 25,000 seats

section B = 14,200 seats

section C = 10,800 seats

Your teacher may want you to leave out the commas from each number.

=============================================================

Work Shown:

A = number of seats in section A
B = number of seats in section B
C = number of seats in section C

A = B+C

A+B+C = 50,000

B+C+B+C = 50,000

2(B+C) = 50,000

B+C = 50,000/2

B+C = 25,000

C = 25,000 - B

25A + 20B + 15C = 1,071,000

25(B+C) + 20B + 15C = 1,071,000

25(25,000) + 20B + 15(25,000 - B) = 1,071,000

625,000 + 20B + 375,000 - 15B = 1,071,000

1,000,000 + 5B = 1,071,000

5B = 1,071,000 - 1,000,000

5B = 71,000

B = (71,000)/5

B = 14,200 is the number of seats in section B

C = 25,000 - B

C = 25,000 - 14,200

C = 10,800 is the number of seats in section C

A = B+C

A = 14,200 + 10,800

A = 25,000 is the number of seats in section A

--------------

Check:

A+B+C = 25,000+14,200+10,800 = 50,000

5 0

2 years ago

A company is approached by a new warehouse management systems vendor to adopt a new system. The vendor claims that the warehouse

Ludmilka [50]

Answer:

a

The null hypothesis is $H_o : \mu = 180$

The alternative hypothesis is $H_a : \mu < 180$

b

The decision rule is fail to reject the null hypothesis

The conclusion

There no sufficient evidence to support the vendor claim that the warehouse management system reduces the average pick, pack, and ship time to below 3 minutes(180 seconds) per order through bin location and routing optimization

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 3 \ minutes = 180 \ seconds$

The sample size is n = 25

The excel sheet is show on the first uploaded image

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu = 180$

The alternative hypothesis is $H_a : \mu < 180$

Generally the sample mean is mathematically represented as

$\= x = \frac{156 + 136 + \cdots + 181}{25}$

=> $\= x = 173.2$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{\frac{\sum (x_i - \= x )^2 }{n} }$

=> $\sigma = \sqrt{\frac{ (156 - 173.2 )^2 + (136 - 173.2 )^2 + \cdots + (181- 173.2 )^2 }{25} }$

=> $\sigma = 24.261$

Generally the test statistics is mathematically represented as

$t = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} } }$

=> $t = \frac{173.2 - 180 }{\frac{24.261}{\sqrt{25} } }$

=> $z = -1.40$

Generally p-value is mathematically represented as

$p-value = P(Z < z)$

=> $p-value = P(Z < -1.40)$

From the z-table

$P(Z < -1.40) = 0.080757$

=> $p-value = 0.080757$

From the obtained value we that $p-value > \alpha$

The decision rule is fail to reject the null hypothesis

The conclusion

There no sufficient evidence to support the vendor claim that the warehouse management system reduces the average pick, pack, and ship time to below 3 minutes(180 seconds) per order through bin location and routing optimization

5 0

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Find the equation of the line passing through the point (-4,6). And having a slop of 1/2

Y_Kistochka [10]

The answer for this question is =
y = 1/2x+ 8

Work
y= mx +b:
y= 1/2x+b
x= -4
y=6
6=1/2(-4)+b
6=-2+b
b=8
y=1/2x+8

6=

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3 years ago

-. Find the value of x. Round to the nearest degree.

Mice21 [21]

X is 44.4 degrees and round it off to the nearest degree is 44

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2 years ago

A company that sells annuities must base the annual payout on the probability distribution of the length of life of the particip

Svetlanka [38]

Answer:

Step-by-step explanation:

Let X be length of life of the participants in the plan.

Given that X is N(68,3.5)

We convert this to standard normal score z using

$z=\frac{x-68}{3.5}$

a) proportion of the plan recipients that would receive payments beyond age 75= $P(X\geq 75) = P(Z\geq 2)\\= 0.025$

b) proportion of the plan recipients die before they reach the standard retirement age of 65= $P(X\leq 65) = P(z\leq -0.86)\\=0.5-0.2764\\=0.2236$

c) x for 86% ceased

$P(Z$

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3 years ago