Sorry bro I don’t understand how to answer that question
solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
Answer:
12.9
Step-by-step explanation:
sin 59 = opposite/hypotenuse
opposite is x, the dimension facing the angle 59
hypotenuse is the longest side = 15
sin 59 = x/15
x = 15sin59 = 15 x 0.8572 =12.858 = 12.9 in the nearest tenth
7x - 6 = 85
7x = 85 + 6
7x = 91
x = 91/7
x = 13......Mrs. Reno is thinking of 13...thats just creepy
Answer:
5+3w
Step-by-step explanation:
make it braintliest please