If an ideal gas has a pressure of 4.03 atm,
1 answer:
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Answer : The mass of copper deposit is, 1.98 grams
Explanation :
First we have to calculate the charge.
Formula used :
where,
Q = charge = ?
I = current = 10 A
t = time = 10 min = 600 sec (1 min = 60 sec)
Now put all the given values in this formula, we get
Now we have to calculate the number of atoms deposited.
As, 1 atom require charge to deposited =
Number of atoms deposited = atoms
Now we have to calculate the number of moles deposited.
Number of moles deposited = moles
Now we have to calculate the mass of copper deposited.
1 mole of Copper has mass = 63.5 g
Mass of Copper Deposited =
Therefore, the mass of copper deposit is, 1.98 grams
Answer:
Step 1;
q = w = -0.52571 kJ, ΔS = 0.876 J/K
Step 2
q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ
Explanation:
The given parameters are;
= 100 N·m
= 327 K
= 90 N·m
Step 1
For isothermal expansion, we have;
ΔU = ΔH = 0
w = n·R·T·ln(/
) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71
w ≈<em> -0.52571</em> kJ
At state 1, q = w = -0.52571 kJ
ΔS = -n·R·ln(/
) = -1 × 8.314 × ln(90/100) ≈ 0.876
ΔS ≈ 0.876 J/K
Step 2
q = 0 for adiabatic process
ΔU = 25×(27 - 327) = -7,500
w = ΔU = <em>-7.5 kJ</em>
ΔH = ΔU + n·R·ΔT
ΔH = -7,500 + 8.3142 × 300 = -5,005.74
ΔH = ΔU = <em>-5.00574 kJ</em>