Give an example of how you could use different reference frames for the same motion.

Chemistry

2 answers:

RUDIKE [14]3 years ago

8 0

Answer:

Motion is defined as a change of position. How we perceive motion depends on our frame of reference. Frame of reference refers to something that is not moving with respect to an observer that can be used to detect motion.

Explanation:

NikAS [45]3 years ago

3 0

Motion is basically just movement in different frames. The person above is better at explaining lol

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Consider the two gaseous equilibria: The values of the equilibrium constants K 1 and K 2 are related by

Sauron [17]

The question is missing parts. The complete question is as follows.

Consider the two gaseous equilibria involving SO2 and the corresponding equilibrium constants at 298K:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$ ; $K_{1}$

$2SO_{3}_{(g)}$ ⇔ $2SO_{2}_{(g)}+O_{2}_{(g)}; K_{2}$

The values of the equilibrium constants are related by:

a) $K_{1}$ = $K_{2}$

b) $K_{2} = K_{1}^{2}$

c) $K_{2} = \frac{1}{K_{1}^{2}}$

d) $K_{2}=\frac{1}{K_{1}}$

Answer: c) $K_{2} = \frac{1}{K_{1}^{2}}$

Explanation: <u>Equilibrium</u> <u>constant</u> is a value in which the rate of the reaction going towards the right is the same rate as the reaction going towards the left. It is represented by letter K and is calculated as:

$K=\frac{[products]^{n}}{[reagents]^{m}}$

The concentration of each product divided by the concentration of each reagent. The indices, m and n, represent the coefficient of each product and each reagent.

The equilibrium constants of each reaction are:

$SO_{2}_{(g)} + \frac{1}{2}O_{2}$ ⇔ $SO_{3}_{(g)}$

$K_{1}=\frac{[SO_{3}]}{[SO_{2}][O_{2}]^{1/2}}$

$2SO_{3}_{(g)}$ ⇔ $2SO_{2}_{(g)}+O_{2}_{(g)}$

$K_{2}=\frac{[SO_{2}]^{2}[O_{2}]}{[SO_{3}]^{2}}$

Now, analysing each constant, it is easy to see that $K_{1}$ is the inverse of $K_{2}$ .

If you doubled the first reaction, it will have the same coefficients of the second reaction. Since coefficients are "transformed" in power for the constant, the relationship is:

$K_{2}=\frac{1}{K_{1}^{2}}$