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Strike441 [17]
2 years ago
8

This equation shows how the cost of a photography session is related to its duration in hours.

Mathematics
1 answer:
joja [24]2 years ago
8 0

Answer:

1 hour

Step-by-step explanation:

c= 20d

here, c=$20

$20=20d

or, d= 1 hr

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Harper scores 24 points per coin. In all, how many coins does Harper have to collect to
Mrac [35]

Answer:

2 coins

Step-by-step explanation:

3 0
3 years ago
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A math textbook has 6 pages of instruction for every 2 pages of practice problems. How many pages of instruction does it have fo
gayaneshka [121]

Answer:

Unit rate is found simply by dividing.

6 pages of instruction/2 pages of practice problems = 3 pages of instruction per page of practice problems

Step-by-step explanation:

6 0
3 years ago
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50 students live in a dormitory. The parking lot has the capacity for 30 cars. Each student has a car with probability 12 , inde
Maurinko [17]

Answer:

P(X is greater than 30) = 0.06

Step-by-step explanation:

Given that:

Sample proportion (p) = 0.5

Sample size = 30

The Binomial can be approximated to normal with:

\mu = np = 50 \times 0.5 \\ \\ \mu= 25

\sigma = \sqrt{np(1-p) } \\ \\  \sigma = \sqrt{50 \times (0.5)(1-0.5) } \\ \\ \sigma = 3.536

To find:

P(X> 30)

So far we are approximating a discrete Binomial distribution using the continuous normal distribution. 30 lies between 29.5 and 30.5

Normal distribution:

x = 30.5, \mu = 25, \sigma = 3.536

Using the z test statistics;

z = \dfrac{x - \mu}{\sigma}

z = \dfrac{30.5 - 25}{3.536}

z = \dfrac{5.5}{3.536}

z = 1.555

The p-value for P(X>30) = P(Z > 1.555)

The p-value for P(X>30) = 1 - P (Z< 1.555)

From the z tables;

P(X> 30) = 1 - 0.9400

Thus;

P(X is greater than 30) = 0.06

7 0
3 years ago
Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

\ln{e^{-12r}} = \ln{0.5}

-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

r = 0.05776

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

e^{-0.05776t} = 0.25

\ln{e^{-0.05776t}} = \ln{0.25}

-0.05776t = \ln{0.25}

0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

t = 24

It would take 24 minutes for the element to decay to 50 grams

6 0
3 years ago
Maggie is rock climbing. After reaching the summit, she descends at a rate of 7 feet each minute. If she continues at this rate,
Slav-nsk [51]

Answer:

she will have gone down 56 feet

8 0
3 years ago
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