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3 years ago

Could someone please show me how to factor this using the x method

Mathematics

2 answers:

34kurt3 years ago

8 0

Answer:

(x + 2) (8x + 3)

Step-by-step explanation:

$8x^{2}$ + $19x + 6$

= (x + 2) (8x + 3)

L = 3/a = 3/8

R = 16/a = 16/8 = 2

ozzi3 years ago

8 0

\ac/

L V R

/ \

/ b \

where letters have their usual meaning. Comparing 8x² + 19x + 6 to ax² + bx + c,

ac = 8*6 = 48

b = 19

Factors of ac or 48 :-

1 * 48

2 * 24

3 * 16

As the sum of 3 and 16 is 19(or b), our required pair is 3 and 16.

On the left side:

L = 3/a = 3/8

On the right side:

R = 16/a = 16/8 = 2

Therefore, factorized form is (x + 3/8)(x + 2) which can be written as (8x + 3)(x + 2).

How this method works:

Make a X with ac and b on the top and bottom of the X, where ac and b are taken from ax² + bx + c.

On the left side we have d/a and e/a. Basically d and e are those values that we get after solving the whole question.

Step1: find the pair(s) for which sum of factors of ac = b. Here it is 3 and 16.

Step2: put these values in place of d and e.

Step3: solve left anf right of X,

Left = d/a = 3/8

Right = e/a = 16/8 = 2

Step4: whatever you get, put that in (x+?)(x+?) in place of ?.

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Peter has money in two savings accounts. One rate is 6% and the other is 14%. If he has $900 more in the 14% account and the tot

-BARSIC- [3]

Answer:

$1375 at 14%
$475 at 6%

Step-by-step explanation:

Let x represent the amount Peter invested at 14%. Then (x-900) is the amount he invested at 6%. His total interest earned is ...

0.14x + 0.06(x -900) = 221

0.20x = 275 . . . . . . . . . . . . . . . . add 54, simplify

x = 1375 . . . . . . . . . . . . . . . . . . . .divide by 0.2; amount invested at 14%

(x-900) = 475 . . . . . . . . . . . . . . . amount invested at 6%

Peter invested $475 in the 6% account and $1375 in the 14% account.

7 0

3 years ago

On a map, Sanford, NC and Myrtle Beach, SC are 4 inches apart. The distance between cities is actually 156 miles. What scale was

defon

Answer:

39 or 1/39

Step-by-step explanation:

You need to divide these but it depends on how you divide them

4/156=1/39
156/4=39

8 0

4 years ago

The exponential model A=302.5e^0.0211 describes the population, A, of a country in millions, t years after 2003. Use the model

Naddik [55]

The population of the country in 2003 is 302.5 million

<h3>How to determine the population of the country in 2003.</h3>

From the question, we have the following parameters that can be used in our computation:

Exponential model, A = 302.5e^0.0211t

Where i is the number of years after 2003

In the year 2003, the value of t is 0

i.e. 0 years after 2003

So, we have

A = 302.5e^(0.0211 * 0)

Evaluate the products

A = 302.5 * 1

So, we have the following result

A = 302.5

Hence, the population is 302.5 million

Read more about exponential models at

brainly.com/question/27161222

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3 0

1 year ago

The sum of two consecutive odd integers is greater than 36 (solve with an inequality and show work please)

mixas84 [53]

O+o+2>36
2o>34
o>17
o1>17
o2>19
o is equal to odd number

4 0

3 years ago

Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -

rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

$y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\$

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by D and its formula is

$D=b^2-4ac\\$

Where

a= the coefficient of the $x^{2}$

b= the coefficient of $x$

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant and evaluate our answer accordingly .

Let us start with

$y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\$

Hence we have two real roots for this equation.

$y = 2x^2 - 6x + 5\\$

$y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D$

Hence we do not have any real root for this quadratic

$y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\$

Hence D>0 and thus we have two real roots for this equation.

$y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\$

Hence we have one real root to this quadratic equation.

7 0

3 years ago