The formula for kinetic energy is: KE = 1/2 x mass x velocity squared. We can plug in the information for the ball into this equation to determine the kinetic energy. The mass is 0.5 kg and the velocity is 10 meters per second. So: KE = (1/2)(0.5)(10)^2. Thus the kinetic energy of the ball is 25 J. The unit Joule (J) is the same as kgm^2/s^2 and is the SI unit for kinetic energy.
Explanation:
Momentum of the system is a constant when there aren't external forces..
So,When first Balls velocity is went down to zero... its momentum is also zero and beacause momentum should be a constant...now second ball must have a momentum of 20 kg * m/s
Explanation:
Vi = 12 m/s
a = 3 m/s^2
t = 2 s
Vf = Vi + a × t = 12 + 3 ×2 = 18 m/s
Answer:
The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.
Explanation:
Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.
Answer is d using a heavier string
