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hichkok12 [17]
3 years ago
10

Given that these triangles are similar, which side corresponds to side GE?

Mathematics
2 answers:
AleksAgata [21]3 years ago
8 0

Answer:

The first one is KL and the second one is FG

Step-by-step explanation

liq [111]3 years ago
7 0

Answer:

1.KL

2.FG

Step-by-step explanation:

I hoped I helped

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find the number of running and passing plays using substitution method 110 plays 3 yards per run 7 yards per pass total yards 37
Zinaida [17]

Let x be the number of running plays

Y  be the number of passing plays

Since the total plays is 110

 X + y = 110

And total yard is 378

3x + 7y = 378

Using the first equation

X = 110 – y and substitute to the 2nd equation

3(110 – y) + 7y = 378

And solve for y

Y = 12

Substitute to eqution 1

X = 110 – 12 = 98

7 0
3 years ago
Q ,# 13 Graph the function<br>Y = - X + X ^2
GalinKa [24]
We have the following function that is a quadratic function:

y=-x+x^2

So the graph of this function is shown in the figure below. This is a <em>parabola</em> as you can see. The roots of this functions, that is, the x-intercepts are:

y=-x+x^2 \\ y=x(x-1) \\ \\ x_{1}=0 \ and \ x_{2}=1

As you can see in the figure. This function decreases from (-\infty,0.5) and increases from (0.5, \infty)

Finally, another thing we can see from the graph is that the vertex is the point:

V(0.5,-0.25)


4 0
4 years ago
Read 2 more answers
Student records suggest that the population of students spends an average of 6.30 hours per week playing organized sports. The p
Ymorist [56]

Answer:

a) 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

b) 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

Step-by-step explanation:

To solve this question, it is important to know the Normal probability distribution and the Central Limit Theorem

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 6.3, \sigma = 2.1, n = 49, s = \frac{2.1}{\sqrt{49}} = 0.3

A) What is the chance HLI will find a sample mean between 5.5 and 7.1 hours?

This is the pvalue of Z when X = 7.1 subtracted by the pvalue of Z when X = 5.5.

By the Central Limit Theorem, the formula for Z is:

Z = \frac{X - \mu}{s}

X = 7.1

Z = \frac{7.1 - 6.3}{0.3}

Z = 2.67

Z = 2.67 has a pvalue of 0.9962

X = 5.5

Z = \frac{5.5 - 6.3}{0.3}

Z = -2.67

Z = -2.67 has a pvalue of 0.0038

So there is a 0.9962 - 0.0038 = 0.9924 = 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

B) Calculate the probability that the sample mean will be between 5.9 and 6.7 hours.

This is the pvalue of Z when X = 6.7 subtracted by the pvalue of Z when X = 5.9

X = 6.7

Z = \frac{6.7 - 6.3}{0.3}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

X = 5.9

Z = \frac{5.9 - 6.3}{0.3}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918.

So there is a 0.9082 - 0.0918 = 0.8164 = 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

5 0
3 years ago
A truck can be rented from Company A for ​$110 a day plus ​$0.80 per mile. Company B charges ​$30 a day plus ​$0.90 per mile to
grin007 [14]

Answer:

800 miles

Step-by-step explanation:

Let the number of miles be represented by x

Company A for ​$110 a day plus ​$0.80 per mile.

$110 + $0.80 × x

110 + 0.80x

Company B charges ​$30 a day plus ​$0.90 per mile to rent the same truck.

$30 + $0.90 × x

30 + 0.90x

110 + 0.80x = 30 + 0.90x

110 - 30 = 0.90x - 0.80x

80 = 0.1x

x = 80/0.1

x = 800 miles

800 miles driven per day makes the rental cost for Company A a better deal than Company​ B's

6 0
3 years ago
What is the simplified form of 15x^8/24y^5 divided by 4x^4/8y^2
Reika [66]
(24y^5)/(15x^8) * 4x^4/(8y²) 

<span>Reduce the common factors for the numerator and denominator and multiply the fractions altogether to get... </span>

<span>24/8 * y^(5 - 2) * 4/15 * 1/x^(8 - 4) </span>
<span>= 3y³ * 4/15 * 1/x^4 </span>
<span>= 4y³/(5x^4) </span>

<span>I hope this helps!</span>
6 0
3 years ago
Read 2 more answers
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