All categories

3 years ago

Given that these triangles are similar, which side corresponds to side GE?

Mathematics

2 answers:

AleksAgata [21]3 years ago

8 0

Answer:

The first one is KL and the second one is FG

Step-by-step explanation

liq [111]3 years ago

7 0

Answer:

1.KL

2.FG

Step-by-step explanation:

I hoped I helped

You might be interested in

Enter the unknown value that makes this statement true 40% of ______ is 60

SpyIntel [72]

40% of 150 is 60. That’s math

7 0

3 years ago

Read 2 more answers

true or false. the absolute value of. number will always be greater than the number itself. justify ur answer

swat32

false have a great day

6 0

2 years ago

Identify the slope and the y-intercept of the line with the given equation: y = 7x-5

svetlana [45]

Answer:

Slope = 7

Y intercept = (0,-5)

7 0

3 years ago

Coal is carried from a mine in West Virginia to a power plant in New York in hopper cars on a long train. The automatic hopper c

svp [43]

Answer:

0.2839 = 28.93%

Step-by-step explanation:

In order to find find the probability that one car chosen at random will have less than 68.5 tons of coal, we have to find z

Le x be tons of coal in a car

Z = (x – mean)/standard deviation

Z = (x – μ)/ σ

P (x<68.5) = P(z < (68.5-69)/0.9)

P (x<68.5) = P(z < -0.5555)

Then we use the z table to find the area under the curve.

P (x<68.5) = 0.2893

5 0

3 years ago

What is the solution of x=2+ square root x-2?

alex41 [277]

So I'm going to assume that this question is asking for non extraneous solutions, or solutions that are found in the equation and are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

$x-2=\sqrt{x-2}$

Next, square both sides:

$(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2$

Next, subtract x and add 2 to both sides of the equation:

$x^2-5x+6=0$

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

$x^2-2x-3x+6=0$

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$x(x-2)-3(x-2)=0$

Now you can rewrite the equation as $(x-3)(x-2)=0$

Now, apply the Zero Product Property and solve for x as such:

$x-3=0\\x=3\\\\x-2=0\\x=2$

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

$2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}$

Since both solutions hold true when x = 2 and x = 3, your answer is C. x = 2 or x = 3.

8 0

3 years ago