1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hichkok12 [17]
3 years ago
10

Given that these triangles are similar, which side corresponds to side GE?

Mathematics
2 answers:
AleksAgata [21]3 years ago
8 0

Answer:

The first one is KL and the second one is FG

Step-by-step explanation

liq [111]3 years ago
7 0

Answer:

1.KL

2.FG

Step-by-step explanation:

I hoped I helped

You might be interested in
What the answer to <br> 4 x 4 x 4
serious [3.7K]
4x 4 x 4 = 64. I hope this helps.
3 0
3 years ago
What is the area of a rectangle with side lenghts 3x+2 and x-4
melamori03 [73]
For a rectangle, A = LW.

A = (3x + 2)(x - 4)

A = 3x^2 - 12x + 2x - 8

A = 3x^2 -10x - 8
6 0
3 years ago
If the sin 90° = 1, then the cos 0° = _____. (1 point)
Cloud [144]
<span>sin 90° = 1
</span>
cos 0° = 1

There's a simple formula : <em>sin θ = cos (90°- θ)</em> or <em>cos θ = sin (90°- θ) </em>

So : cos 0° = sin (90° - 0°) = sin 90° = 1


7 0
3 years ago
Read 2 more answers
The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?
Lina20 [59]
\frac{d}{dx}(y^2 + (xy+1)^3 = 0)&#10;\\&#10;\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0&#10;\\&#10;\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0&#10;\\&#10;\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0&#10;\\&#10;\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0&#10;\\&#10;\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0&#10;\\&#10;\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0&#10;\\&#10;\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right)  (xy+1)^2 = 0&#10;\\&#10;\\2y\ y' + \left(3y+3x\ y'\right)  (xy+1)^2 = 0&#10;\\&#10;\\2y\ y' + \left(3y+3x\ y'\right)  ((xy)^2+2xy+1) = 0&#10;\\&#10;\\2y\ y' + \left(3y+3x\ y'\right)  ((xy)^2+2xy+1) = 0&#10;\\&#10;\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0&#10;\\&#10;\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0&#10;\\&#10;\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y&#10;&#10;
y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1&#10;\\&#10;\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}&#10;\\&#10;\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}&#10;\\&#10;\\y' = \frac{12 -12+3}{(6 -24-12-2 )}&#10;\\&#10;\\y' = \frac{3}{( -32 )}

7 0
3 years ago
A cylindrical can of cocoa has the dimensions shown at the right.
IRINA_888 [86]

Answer:

What are the dementions? 9 and 2?

That would be 9*3.14*4 = 133.04

~ 133.04 units cubed

Step-by-step explanation:

8 0
2 years ago
Other questions:
  • What is the length of each side?label each side with an expression that represents its length
    13·1 answer
  • Find n so that number sentence below is true and explain your answer, referencing the relevant properties of exponents
    12·1 answer
  • Simplify in standard form 10a(-6a^2+2a-7)
    7·1 answer
  • Lex read 7 fewer books than Leona how many books did Leona read
    10·1 answer
  • A biologist finds that a triangular area near a pond is a habitat for storks. The side lengths of the area are 15 meters, 25 met
    6·2 answers
  • Convert each part of the ratio to percentage<br>(a) 3:1<br>(b) 2:3:5<br>(c) 1:4<br>(d) 1:2:5<br>​
    12·1 answer
  • What is the volume of a object whose disney is 10.5 gml and has a mass of 100 gr
    9·1 answer
  • Hey let’s talk about guns are they good or bad
    6·1 answer
  • Triangle GHJ with vertices G(-2, 4), H(3, 6), and J(3, -2) is dilated by a factor of 1/3 centered at the origin. What are the co
    11·1 answer
  • Lol help lol okeasey
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!