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Svetllana [295]
3 years ago
14

Two investments were made totaling $15000. for a certain year these investments yielded $1432 in simple interest. part of the $1

5000 was invested at 9% and part at 10%. find the amount invested at each rate
Business
1 answer:
Andrews [41]3 years ago
3 0
<span>Let amount invested at 9% be "x"; Interest on this is 0.09x dollars Amt. invested at 10% is "15000-x" ; Interest on this is 0.1(15000-x)=1500-0.1x dollars EQUATION: interext + interest=1432 dollars 0.09x + 1500-0.10x = 1432 -0.01x = -68 x=$6800 (amt invested at 9%) 15000-6800=$8200 (amt invested at 10%)</span>
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