Answer:
co-ordinates are (-3,7) and (5,7)
or
(-3,-5) and (5,-5)
length of diagonal=10 units
Step-by-step explanation:
![length=\sqrt{(5+3)^2+(1-1)^2} =\sqrt{64} =8\\slope ~of~length=\frac{1-1}{5+3} =0\\\\length ~of~rectangle~is~parallel~to~x-axis\\ width~ is~ parallel ~to~y- axis~and~is~6~units~away~from~length.\\other co-ordinates ~of~rectangle are~(-3,1+6)~and ~(5,1+6)~or~(-3,7)~and~(5,7)\\and~other~co-ordinates~are~(-3,1-6)~and~(5,1-6)~or~(-3,-5)~and~(5,-5)](https://tex.z-dn.net/?f=length%3D%5Csqrt%7B%285%2B3%29%5E2%2B%281-1%29%5E2%7D%20%3D%5Csqrt%7B64%7D%20%3D8%5C%5Cslope%20~of~length%3D%5Cfrac%7B1-1%7D%7B5%2B3%7D%20%3D0%5C%5C%5C%5Clength%20~of~rectangle~is~parallel~to~x-axis%5C%5C%20width~%20is~%20parallel%20~to~y-%20axis~and~is~6~units~away~from~length.%5C%5Cother%20co-ordinates%20~of~rectangle%20are~%28-3%2C1%2B6%29~and%20~%285%2C1%2B6%29~or~%28-3%2C7%29~and~%285%2C7%29%5C%5Cand~other~co-ordinates~are~%28-3%2C1-6%29~and~%285%2C1-6%29~or~%28-3%2C-5%29~and~%285%2C-5%29)
length of diagonal
d=\sqrt{8^2+6^2} =\sqrt{64+36} =\sqrt{100} =10 ~units\\or\\d=\sqrt{(5+3)^2+(1-7)^2} =\sqrt{64+36} =\sqrt{100} =10~units.
(Volume for a rectangular shape is length x width x height)
We can split up this 3D composite figure into two main parts (as shown in the picture I attached), and find each part’s volume before adding them together for the total volume.
Cube —> 5x5x5 —> 25x5 = 125 in^3
Rectangular Prism —> 20x5x5 —> 100x5 = 500 in^3
125 + 500 = 625
So the answer is A. 625 in^3
Hope this helped! If I was correct, I’d appreciate it if you marked my answer as Brainliest.
Answer:
Step-by-step explanation:
First you would multiply 4x12 l
next you will get 36l
Finally you would divide it by some # to get your answer .
Answer:
The possible error made by Beth is directly multiplying scale of 5 to area of original triangle and getting area of enlarged triangle, which is wrong.
Step-by-step explanation:
Originally Triangle has height =3.5cm and width=4cm
Beth enlarged the same triangle by scale of 5 and calculate area of triangle
The area of triangle as given as A= $$\frac{1}{2} \texrm{ (base) (height)}$$
Area of original triangle is A =$$\frac{1}{2}(3.5 \times 4)$$
Since, The triangle is enlarged by scale of 5
New height =3.5x5 = cm and new width=4x5cm
Area of new triangle is
A' = $$\frac{1}{2} (\textrm{new width} ) ( \textrm{new height})$$
A' = $$\frac{1}{2}(3.5 \times 5)(4\times 5)$$
A' = $$\frac{1}{2}(3.5 \times 4)(5^{2})$$
A' = $$A (5^{2})$$
Now, Looking what error beth made is:
Beth found Area of new triangle is A' = $$\frac{1}{2}(3.5)(4)(5)$$
The possible error made by Beth is directly multiplying scale of 5 to area of original triangle and getting area of enlarged triangle, which is wrong.
Answer:
800%
Step-by-step explanation:
The pyramid has a volume equal to (14)^2*(6/3)=392. The pyramid B is (3136)/(392)=8 times bigger than pyramid A. As a percentage, it's 800%