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myrzilka [38]
3 years ago
12

What element is Column 1, period 3

Chemistry
1 answer:
Finger [1]3 years ago
3 0

Answer:

Sodium (Na)

Explanation:

The element on the periodic table at Column (group) 1, period 3 is Sodium (Na)

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Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
3 years ago
What are the reactants and products when butane combusts with excess oxygen?
larisa86 [58]
C3H8 + O2 --> CO2(g) + H2O(g) + energy(heat)

butane + oxygen --> carbon dioxide + water + heat 
7 0
3 years ago
Choose the atom or ion that is larger.<br><br> Select one:<br> a. Br-1<br> b. Br
solniwko [45]

Answer:

Br^-1

Explanation:

It is an ion that gained an extra electron making it 36 electrons but the other. one is in the neutral state with 35 electrons

7 0
2 years ago
How many grams of h3po4 are in 255 ml of a 4.50 m solution of h3po4?
murzikaleks [220]

H3PO4 has molecular weight of approximately 98 grams per mole. 4.50 M is equal to 4.50 mole per 1000 mL solution of H3PO4. 255 mL times 4.50 mol /1000 mL times 98 g/mol is equal to 112.455 grams. Note that I automatically equate 1 Liter to 1000 mL since the given volume is in mL for easier computation.

7 0
3 years ago
Please Help! I will give a Brainliest and 18 points! Please do not give me a random, gibberish answer or I will report you and g
3241004551 [841]

Answer:

V2 = 600ml

Explanation:

dilution principle formula

M1V1 = M2V2

C1V1 = C2V2

3 X 20 = 0.1 x V2

60 = 0.1 x V2

V2 = 60/0.1

V2 = 600ml

pls give brainliest

5 0
3 years ago
Read 2 more answers
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