Explanation:
<h2><em><u>SOLUTION</u></em><em><u>:</u></em></h2>
<em>Solution is a homogenous mixture of two or more substances in relative amounts that can be varied continuously up to what is called the limit of solubility. </em>
<h2><em><u>COLLOID</u></em><em><u>:</u></em></h2>
<em>A mixture in which one substance is divided into minute particles (called colloidal particles) and dispersed throughout a second substance</em>
<h2><em><u>SUSPEN</u></em><em><u>SION</u></em><em><u>:</u></em></h2>
<em>A suspension is a heterogeneous mixture of a finely distributed solid in a liquid. The solid is not dissolved in the liquid, as is the case with a mixture of salt and water. </em>
Answer:
Mass = 76.176 g
Explanation:
Given data:
Mass of lead(II) chloride produced = 62.9 g
Mass of lead(II) nitrate used = ?
Solution:
Chemical equation:
Pb(NO₃)₂ + 2HCl → PbCl₂ + 2HNO₃
Number of moles of lead(II) chloride:
Number of moles = mass/molar mass
Number of moles = 62.9 g/ 278.1 g/mol
Number of moles = 0.23 mol
Now we will compare the moles of lead(II) chloride with Pb(NO₃)₂ from balance chemical equation:
PbCl₂ : Pb(NO₃)₂
1 : 1
0.23 : 0.23
Mass of Pb(NO₃)₂:
Mass = number of moles × molar mass
Mass = 0.23 mol × 331.2 g/mol
Mass = 76.176 g
Answer:
C20 H14 O2
Explanation:
Remark
This is a sample, which the question does not say and should. It is a fraction of 1 mole. So what you have to do is multiply the numbers given by x and equate it to 286.28
Equation
150,86* x + 8.86*x + 20.1*x = 286.28
179.8x = 286.28
x = 286.26/179.8
x = 1.592
Now multiply the given numbers by 1.592
150.86 * 1.592 = 240.58
8.85 * 1.592 = 14.1
20.1 * 1.592 = 32
Rounding you get
240/12 = 20
14.1/1 = 14
32/16 = 2
C20 H14 O2
Given the molarity of the solution is
.
The volume of the solution is 10.9/1000 L
Number of moles of HCl = Molarity * volume of the solution in L
Number of moles of HCl =*
Number of moles of HCl = 2.7 moles.
Therefore number of moles of HCl in 10.9 ml of the stomach acid is 2.7 moles
