Question

if 4.50 mol of ethane, c_(2)h_(6),undergo combustion according to the equation below , how many moles of oxygen are required? 2C_(2)H_(6)+7O_(2 )->4CO_(2)+6H_(2)O

Answer 1

15.75 moles of oxygen is required for 4.5 mole of ethane.

What is a Combustion Reaction ?

The reaction in which a fuel  gets oxidized by an oxidizing agent is called a Combustion Reaction , releasing a large amount of energy is called Combustion Reaction.

It is given in the question that

4.50 mole of ethane undergoes Combustion

2C₂H₆   +  7O₂   ->  4CO₂  +6H₂O

Mole fraction of ethane to oxygen is 2:7

Moles of ethane = 4.5

4.5 /x = 2/7

4.5 * 7 / 2 = x

x = 15.75 moles.

Therefore 15.75 moles of oxygen is required for 4.5 mole of ethane.

To know more about Combustion Reaction

brainly.com/question/12172040

#SPJ1