15.75 moles of oxygen is required for 4.5 mole of ethane.
<h3>What is a Combustion Reaction ?</h3>
The reaction in which a fuel gets oxidized by an oxidizing agent is called a Combustion Reaction , releasing a large amount of energy is called Combustion Reaction.
It is given in the question that
4.50 mole of ethane undergoes Combustion
2C₂H₆ + 7O₂ -> 4CO₂ +6H₂O
Mole fraction of ethane to oxygen is 2:7
Moles of ethane = 4.5
4.5 /x = 2/7
4.5 * 7 / 2 = x
x = 15.75 moles.
Therefore 15.75 moles of oxygen is required for 4.5 mole of ethane.
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