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NikAS [45]
2 years ago
10

if 4.50 mol of ethane, c_(2)h_(6),undergo combustion according to the equation below , how many moles of oxygen are required? 2C

_(2)H_(6)+7O_(2 )->4CO_(2)+6H_(2)O
Chemistry
1 answer:
alexira [117]2 years ago
4 0

15.75 moles of oxygen is required for 4.5 mole of ethane.

<h3>What is a Combustion Reaction ?</h3>

The reaction in which a fuel  gets oxidized by an oxidizing agent is called a Combustion Reaction , releasing a large amount of energy is called Combustion Reaction.

It is given in the question that

4.50 mole of ethane undergoes Combustion

2C₂H₆   +  7O₂   ->  4CO₂  +6H₂O

Mole fraction of ethane to oxygen is 2:7

Moles of ethane = 4.5

4.5 /x = 2/7

4.5 * 7 / 2 = x

x = 15.75 moles.

Therefore 15.75 moles of oxygen is required for 4.5 mole of ethane.

To know more about Combustion Reaction

brainly.com/question/12172040

#SPJ1

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8 0
3 years ago
1. Starting with 9.3 moles of O 2 , how many moles of H 2 S will be needed and how many moles of SO 2 will
enyata [817]

Answer:

Moles of H₂S needed = 6.2 mol

Moles of SO₂ produced = 6.2 mol

Explanation:

Given data:

Number of moles of O₂ = 9.3 mol

Moles of H₂S needed = ?

Moles of SO₂ produced = ?

Solution:

Chemical equation:

2H₂S + 3O₂      →    2SO₂ + 2H₂O

Now we will compare the moles of oxygen with H₂S.

                  O₂             :           H₂S

                    3             :             2

                   9.3            :         2/3×9.3 = 6.2 mol

Now we will compare the moles of SO₂ with both reactant.

                   O₂             :            SO₂

                    3              :               2

                   9.3            :         2/3×9.3 = 6.2 mol      

                 H₂S             :            SO₂

                    2              :               2

                   6.2            :          6.2 mol      

So 6.2 moles of  SO₂ are produced.

         

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