if 4.50 mol of ethane, c_(2)h_(6),undergo combustion according to the equation below , how many moles of oxygen are required? 2C

Question

NikAS [45]

2 years ago

10

if 4.50 mol of ethane, c_(2)h_(6),undergo combustion according to the equation below , how many moles of oxygen are required? 2C

_(2)H_(6)+7O_(2 )->4CO_(2)+6H_(2)O

Chemistry

1 answer:

alexira [117] · Answer 1 · 2023-05-08T17:08:51+03:00

15.75 moles of oxygen is required for 4.5 mole of ethane.

<h3>What is a Combustion Reaction ?</h3>

The reaction in which a fuel gets oxidized by an oxidizing agent is called a Combustion Reaction , releasing a large amount of energy is called Combustion Reaction.

It is given in the question that

4.50 mole of ethane undergoes Combustion

2C₂H₆ + 7O₂ -> 4CO₂ +6H₂O

Mole fraction of ethane to oxygen is 2:7

Moles of ethane = 4.5

4.5 /x = 2/7

4.5 * 7 / 2 = x

x = 15.75 moles.

Therefore 15.75 moles of oxygen is required for 4.5 mole of ethane.

To know more about Combustion Reaction

brainly.com/question/12172040

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