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3 years ago

Help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Natalka [10]3 years ago

3 0

15!!! is the answer to your question:)

Black_prince [1.1K]3 years ago

3 0

The answer to your question is 15 hopefully this helps

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What’s the y-intercept? i found the slope already.

Valentin [98]

Answer:

3.5

Step-by-step explanation:

3.5 is the y-intercept because the point is (0,3.5). This is where it intercepts with the y-axis.

Hope it helps!

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3 years ago

Jaden is building a fence around his yard. He wants to know how much fencing he needs. His yard is shaped like a rectangle that

Ivahew [28]

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4 years ago

Sarah need 7 tickets, how much does it cost if 9 tickets cost 159 dollars

natulia [17]

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I think it's $123

Step-by-step explanation:

good luck!!!and have a great day/night (different time zones)

3 0

3 years ago

Read 2 more answers

ASK YOUR TEACHER An experiment to compare the tension bond strength of polymer latex modified mortar (Portland cement mortar to

mars1129 [50]

Answer:

Test statistics = 3.74

P-value = 0.0001

Step-by-step explanation:

We are given that an experiment to compare the tension bond strength of polymer latex modified mortar to that of unmodified mortar resulted in x = 18.11 kg f/ $cm^{2}$ for the modified mortar (m = 42) and y = 16.83 kg f/ $cm^{2}$ for the unmodified mortar (n = 30).

Assume that the bond strength distributions are both normal and assuming that σ1 = 1.6 and σ2 = 1.3.

Let $\mu_1$ = true average tension bond strengths for the modified mortars

$\mu_2$ = true average tension bond strengths for the unmodified mortars

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2=0$ or $\mu_1=\mu_2$ {means that true average tension bond strengths for the modified and unmodified mortars are same}

Alternate Hypothesis, $H_a$ : $\mu_1-\mu_2>0$ or $\mu_1>\mu_2$ {means that the true average tension bond strengths for the modified mortars is greater than that for unmodified mortars}

The test statistics that will be used here is Two-sample z test statistics as we know about population standard deviations;

T.S. = $\frac{(x-y)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{m}+\frac{\sigma_2^{2} }{n} } }$ ~ N(0,1)

where, x = sample mean tension bond strengths for the modified mortars = 18.11 kg f/ $cm^{2}$

y = sample mean tension bond strengths for the unmodified mortars = 16.83 kg f/ $cm^{2}$

$\sigma_1$ = population standard deviation for modified mortars = 1.6

$\sigma_2$ = population standard deviation for unmodified mortars = 1.3

m = sample of modified mortars = 42

n = sample of unmodified mortars = 30

So, test statistics = $\frac{(18.11-16.83)-(0)}{\sqrt{\frac{1.6^{2} }{42}+\frac{1.3^{2} }{30} } }$

= 3.74

Now, P-value is given by the following formula;

P-value = P(Z > 3.74) = 1 - P(Z $\leq$ 3.74)

= 1 - 0.9999 = 0.0001

Here, the above probability is calculated by looking at the value of x = 3.74 in the z table which gives an area of 0.9999.

5 0

4 years ago

lines A and B are parallel lines cut by transversal, t which of the following equations could be used to find the value of x?

Fiesta28 [93]

Answer:

Step-by-step explanation:

When 2 parallel lines are cut by transversal, it creates 4 pairs of equal angles.

If you see the top "cutting" part, we can say "13x - 15" angle and the angle beside is a straight angle (180 degrees), so their sum is 180. Also, vertically with the "13x - 15" angle, there is another angle, that also creates a line, so their sum would be 180 as well.

Now, the angle "22x + 9" goes same in the below part of the "cutting" point. They are the same angles as the 4 angles on top "cutting" part.

Thus, we can say "13x - 15" and "22x +9" are corresponding angles and they are EQUAL in measure.

So, we can write the equation:

13x - 15 = 22x + 9

THen we can solve for "x".

Equation H is right.

3 0

3 years ago