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suter [353]
3 years ago
14

Help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Natalka [10]3 years ago
3 0
15!!! is the answer to your question:)
Black_prince [1.1K]3 years ago
3 0
The answer to your question is 15 hopefully this helps
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Write each fraction or mixed number as a decimal. 2/5
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Answer:

2 / 5 = 0.4

1 / 5 = 0.2

3 / 4 = 0.75

3 / 5 = 0.6

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Paul has a spinner with 4 colors: green, yellow, blue, and orange. he spins the spinner 60 times and records each color it stops
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Which of these is the x-intercept of x=3?
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3 years ago
You are at a family reunion and the cooler contains ten bottles of soda; four Sprite, three Dr. Pepper, and three Cherry Coke. T
andrew11 [14]

Answer:

<em></em>Probability = \frac{18}{1860480}<em></em>

<em></em>

Step-by-step explanation:

Given

Soda = 10

Sprite = 4

Dr. Pepper = 3

Cherry Coke = 3

Required

Determine the probability of picking Dr. pepper the fourth and fifth

First, we need to sum up the number of drinks

Total = 10 + 4 + 3 + 3

Total = 20

First Selection: Dr. Pepper

P_1= \frac{3}{20}

Since its probability without replacement;

<em>At this stage: Dr. Pepper = 2 and Total = 19</em>

Second Selection: Cherry Coke

P_2= \frac{3}{19}

<em>At this stage: Dr. Pepper = 2; Cherry Coke = 2 and Total = 18</em>

<em></em>

Third Selection: Cherry Coke

P_3= \frac{2}{18}

P_3= \frac{1}{9}

<em>At this stage: Dr. Pepper = 2; Cherry Coke = 1 and Total = 17</em>

<em></em>

Fourth Selection: Dr. Pepper

P_4= \frac{2}{17}

<em>At this stage: Dr. Pepper = 1; Cherry Coke = 1 and Total = 16</em>

<em></em>

Fifth Selection: Dr. Pepper

P_5= \frac{1}{16}

<em></em>

<em>Multiply the calculated probabilities, to give the required probability</em>

<em></em>Probability = P_1 * P_2 * P_3 * P_4 * P_5<em></em>

<em></em>Probability = \frac{3}{20} * \frac{3}{19} * \frac{1}{9} * \frac{2}{17} * \frac{1}{16}<em></em>

<em></em>Probability = \frac{3 * 3 * 1 * 2 * 1}{20 * 19 * 18 * 17 * 16}<em></em>

<em></em>Probability = \frac{18}{1860480}<em></em>

8 0
3 years ago
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