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Nutka1998 [239]

2 years ago

8

Direct Variation

2 answers:

Natalija [7]2 years ago

8 0

Answer:

C. 72

Step-by-step explanation:

I calculated it logically

evablogger [386]2 years ago

7 0

Answer:

<h2>A. - 72 </h2>

Step-by-step explanation:

<h2>Hope it help </h2>

<h2>& studywell ❤️❤️❤️</h2>

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A cat is stuck in a tree. A firefighters 15-foot ladder is the leaning against a tree. The ladder and the ground form a 62° angl

artcher [175]

To solve this problem you must apply the proccedure shown below:

1. You have:

Sinα=opposite/hypotenuse

α=62°
opposite=x
hypotenuse=15 ft

2. When you substitute the values into Sinα=opposite/hypotenuse, you obtain:

Sinα=opposite/hypotenuse
Sin(62°)=x/15

3. You must clear "x", as below:

x=(15)(Sin(62°))
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3 years ago

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Funny cause I just did something similar a few minutes ago

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2 years ago

If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the

denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

$\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)$

Now at head wind → $720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)$

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

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By dividing the top number by the bottom.

Step-by-step explanation:

ummmmm

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Step-by-step explanation:

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3 years ago

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