$14.4
0.8 * 18 = 14.4
Mark brainliest please
Answer:C' = 7-230000/x^2
Step-by-step explanation:
Min occurs when C'=0
0=7-230000/x^2
230000/x^2=7
230000=7x^2
32857.128 = x^2
181.265 = x
Out of range.
So the min must be at an endpoint.
C(1) = 7+230000 = 230007
C(100) = 700+2300 = 3000
Since C(100)<C(1), C(100) is the minimum on the interval [1, 100]
The order size that will minimize cost is 100 units.
Answer:
Option B is the correct answer
Step-by-step Explanation:

Answer:
The zeros of the quadratic polynomial are
and
The relationship between its zeroes and coefficients in the procedure
Step-by-step explanation:
step 1
Find the zeros
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
step 2
Find the sum of the zeros and the product of the zeros
<u><em>Sum of the zeros</em></u>
<u><em>Product of the zeros</em></u>
step 3
Verify that
Sum of the zeros= -Coefficient x/Coefficient x²
Coefficient x=-24
Coefficient x²=4√5
substitute

therefore
the relationship is verified
step 4
Verify that
Product of the zeros= Constant term/Coefficient x²
Constant term=-9√5
Coefficient x²=4√5
substitute

therefore
the relationship is verified
Answer:
(-2, 3)
Step-by-step explanation:
The point B is:
B(x,y)
x
AB(A to B) is twice BC(B to C)
AB is 2 - x. BC is x - (-4) = x + 4.
So
2 - x = 2(x + 4)
2 - x = 2x + 8
3x = -6
x = -2
y
Same logic as above.
AB is -5 - y. BC is y - 7.
-5 - y = 2(y - 7)
-5 - y = 2y - 14
3y = 9
y = 3
The point is (-2, 3).