AD _____ EC Choose the relationship symbol to make a true statement. = >

The regular price of a t-shirt is 18 dollars. What price will you pay after a 20% discount

neonofarm [45]

$14.4

0.8 * 18 = 14.4

Mark brainliest please

8 0

3 years ago

Read 2 more answers

Please answer now, 50 points!

dimulka [17.4K]

Answer:C' = 7-230000/x^2

Step-by-step explanation:

Min occurs when C'=0

0=7-230000/x^2

230000/x^2=7

230000=7x^2

32857.128 = x^2

181.265 = x

Out of range.

So the min must be at an endpoint.

C(1) = 7+230000 = 230007

C(100) = 700+2300 = 3000

Since C(100)<C(1), C(100) is the minimum on the interval [1, 100]

The order size that will minimize cost is 100 units.

6 0

4 years ago

Find x. A. 6√2 B. 2√2 C. 4 D. 2–√

Alekssandra [29.7K]

Answer:

Option B is the correct answer

Step-by-step Explanation:

$\sin 45 \degree = \frac{x}{2} \\ \\ \frac{1}{ \sqrt{2} } = \frac{x}{2} ..( \because \: \sin 45 \degree =\frac{1}{\sqrt 2}) \\ \\ \huge \purple{ \boxed{ x = \frac{ \sqrt{2} }{2}}} \\ \\$

8 0

4 years ago

find the zeros of the quadratic polynomial 4√5x^2-24x-9√5 and verify its relationship between its zeroes and coefficients.......

Bas_tet [7]

Answer:

The zeros of the quadratic polynomial are

$x=\frac{15\sqrt{5}}{10}$ and $x=-\frac{3\sqrt{5}}{10}$

The relationship between its zeroes and coefficients in the procedure

Step-by-step explanation:

step 1

Find the zeros

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$4\sqrt{5}x^{2}-24x-9\sqrt{5}=0$

so

$a=4\sqrt{5}\\b=-24\\c=-9\sqrt{5}$

substitute in the formula

$x=\frac{-(-24)(+/-)\sqrt{-24^{2}-4(4\sqrt{5})(-9\sqrt{5})}} {2(4\sqrt{5})}$

$x=\frac{24(+/-)\sqrt{-24^{2}-4(4\sqrt{5})(-9\sqrt{5})}} {8\sqrt{5}}$

$x=\frac{24(+/-)\sqrt{1,296}} {8\sqrt{5}}$

$x=\frac{24(+/-)36} {8\sqrt{5}}$

$x=\frac{24(+)36} {8\sqrt{5}}=\frac{15\sqrt{5}}{10}$

$x=\frac{24(-)36} {8\sqrt{5}}=-\frac{3\sqrt{5}}{10}$

step 2

Find the sum of the zeros and the product of the zeros

Sum of the zeros

$(\frac{15\sqrt{5}}{10})+(-\frac{3\sqrt{5}}{10})=\frac{12\sqrt{5}}{10}=\frac{6\sqrt{5}}{5}$

Product of the zeros

$(\frac{15\sqrt{5}}{10})*(-\frac{3\sqrt{5}}{10})=-\frac{9}{4}$

step 3

Verify that

Sum of the zeros= -Coefficient x/Coefficient x²

Coefficient x=-24

Coefficient x²=4√5

substitute

$\frac{6\sqrt{5}}{5}=-(-24)/4\sqrt{5}\\ \\\frac{6\sqrt{5}}{5}=\frac{6\sqrt{5}}{5}$

therefore

the relationship is verified

step 4

Verify that

Product of the zeros= Constant term/Coefficient x²

Constant term=-9√5

Coefficient x²=4√5

substitute

$-\frac{9}{4}=(-9\sqrt{5})/4\sqrt{5}\\ \\-\frac{9}{4}=-\frac{9}{4}$

therefore

the relationship is verified

8 0

3 years ago

Find the coordinates of point b on ac such that the ratio of AB to BC is 2:1

AnnyKZ [126]

Answer:

(-2, 3)

Step-by-step explanation:

The point B is:

B(x,y)

x

AB(A to B) is twice BC(B to C)

AB is 2 - x. BC is x - (-4) = x + 4.

So

2 - x = 2(x + 4)

2 - x = 2x + 8

3x = -6

x = -2

y

Same logic as above.

AB is -5 - y. BC is y - 7.

-5 - y = 2(y - 7)

-5 - y = 2y - 14

3y = 9

y = 3

The point is (-2, 3).

3 0

4 years ago