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sertanlavr [38]
3 years ago
10

What represents acceleration on a velocity vs. time graph

Physics
1 answer:
nikklg [1K]3 years ago
8 0
What represents acceleration on a velocity time graph is THE SLOPE OF THE GRAPH.
The slope of a velocity time graph represent the acceleration of the object, that is, the value of the slope at a particular time represent the acceleration of the object at that point in time. 
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You live on a planet far from ours. "Based on extensive communication with a physicist on earth", you have determined that all l
Ugo [173]

Answer:

8.56 m/s2

Explanation:

Using law of energy conservation while taking into account of the rotational and translation kinetic energy, when the solid cylinder rolls down the incline we have the potential energy converted to kinetic energy:

E_p = E_{kv} + E_{k\omega}

mgh = mv^2/2 + I\omega^2/2

where m is the mass, I = mr^2/2 is the moments of inertia of the solid cylinder \omega = v / r is the angular speed of the cylinder

mgh = mv^2/2 + \frac{mr^2}{2}\frac{(v/r)^2}{2}

mgh = mv^2/2 + mv^2/4 = 3mv^2/4

h = 3v^2/(4g)

So if you plot a liner chart of h vs v^2 and get a slope of 6.42 then that means 3/(4g) = 6.42 so g = 6.42*4/3 = 8.56 m/s^2

The gravitational acceleration on this planet is 8.56 m/s2

3 0
4 years ago
Juan compró un carro que dicen que es muy rápido. Cuándo lo probó recorrió una distancia de 4500m en tan solo 5 min. ¿Qué veloci
sweet [91]

Answer:

Don't know sorry..................

4 0
3 years ago
Scientists experimenting with two charged objects of 2.56 x 10-6 C and 3.34 x 10-7 C displayed a repulsion of 2.26 x 10-3 N. How
Pachacha [2.7K]

Answer:

The objects were 1.8m apart.

Explanation:

We will start stating the Coulomb's Law. It says that:

F_e=\frac{Kq_1q_2}{r^{2}}

Where F_e is the electric force between the objects, q_1 and q_2 are the magnitude of the charge of the objects, r is the distance between them and K is the Coulomb's constant (K=8.9*10^{9} \frac{Nm^{2} }{C^{2} } in vacuum). Solving for the distance r we have:

r=\sqrt{\frac{Kq_1q_2}{F_e} }

Plugging the given values into this equation, we obtain:

r=\sqrt{\frac{(8.9*10^{9}\frac{Nm^{2} }{C^{2} })(2.56*10^{-6}C)(3.34*10^{-7}C)}{2.26*10^{-3}N}}=1.8m

In words, the two charged objects were 1.8m apart.

6 0
3 years ago
Read 2 more answers
How many protons are in the nucleus of an aluminum atom
zlopas [31]
The atomic number of Aluminum is 13. The atomic number represents the number of protons in an atom.
6 0
3 years ago
Read 2 more answers
How far apart must two protons be if the electrical force acting on either one is equal to its weight on the earth's surface whe
BARSIC [14]

Answer:

G M m / R^2 = F   force of attraction for proton

K e^2 / r^2 = F     force of attraction between 2 protons

G M m / R^2 = K e^2 / r^2

r^2 = K e^2 R^2 / (G M m)

r^2 = 9E9 * (1.6E-19)^2 * (6.37E6)^2 / (6.67E-11 * 5.98E24 * 1.7E-27)

r^2 = 9 * 2.56 * 40.6 / (6.67 * 5.98 * 1.7) * 10^-19

r^2 = 1.38 * 10^-30

r = 1.17E-15 m

7 0
3 years ago
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