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sertanlavr [38]
3 years ago
10

What represents acceleration on a velocity vs. time graph

Physics
1 answer:
nikklg [1K]3 years ago
8 0
What represents acceleration on a velocity time graph is THE SLOPE OF THE GRAPH.
The slope of a velocity time graph represent the acceleration of the object, that is, the value of the slope at a particular time represent the acceleration of the object at that point in time. 
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Campaign against crime​
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Explanation:

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A capoeira é muito mais que uma luta, por isso os campeonatos internos tem o objetivo de: 1 ponto Testar a força dos participant
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All of the following are examples of electric current except _______.
Aleks04 [339]
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3 years ago
What is the acceleration of a car initially traveling at -5m/s and<br> reaching -22m/s in 3s.
lozanna [386]

Answer:

a=-5.67\ m/s^2

Explanation:

Given that,

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Final velocity, v = -22 m/s

Time, t = 3s

We need to find the acceleration of the car. The formula of it is given by :

Acceleration,

a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2

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4 0
3 years ago
In the diagram, q1 = +6.39*10^_9 C and
ivanzaharov [21]

Answer:

The electric potential will be "259.695 volt".

Explanation:

In the given question, the figure is not provided. Below is the attached figure given.

Given:

q_1=6.39\times 10^{-9} \ C

q_2=3.22\times 10^{-9} \ C

AP=(0.150+0.250)

      =0.40 \ m

BP=0.25 \ m

Now,

At point P, the electric potential will be:

⇒ V=\frac{q_1}{4 \pi \epsilon_o AP } +\frac{q_2}{4 \pi \epsilon_o BP}

By putting values, we get

⇒     =9\times 10^9 [\frac{6.39\times 10^{-9}}{0.40} +\frac{3.22\times 10^{-9}}{0.25} ]

⇒     =259.695 \ Volt

4 0
3 years ago
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