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Kitty [74]
3 years ago
14

8. Contrast. The energy that can be released during a nuclear fission reaction with the energy that can be released during a nuc

lear fission reaction.
9. Contest. Alpha particles, beta particles, and gamma rays


10. Explain. Why mass-energy equivalence is not apparent for chemical reactions


11. Think critically. Explain why high temperatures are needed for fission reactions to occur but not for fission reactions to occur
Physics
1 answer:
Cloud [144]3 years ago
7 0
8) the energy released by fusion is generally 3 to 4 times larger than with fission.  Fission has very few by-products but fusion releases large amounts of radioactive particles because it starts with large nuclei.
9) Alpha particles are 2 protons and 2 neutrons all put together.  It's really the nucleus of a helium atom.  It is most dangerous if you ingest it but it can be stopped with a sheet of paper so outside the body it's not as dangerous as others and due to its size it can't get very far in the air before hitting air molecules
beta particles are high energy electrons or positrons.  They travel further due to their small size but can be stopped by a thin barrier of plastic or wood.
Gamma rays are high frequency photons (light)  They are stopped by metal plates and go through human tissue.  They are quite dangerous.
10) The mass that is lost in chemical reactions is very small. Solve E=mc² for mass and you get m=E/c².  This says the mass you lose is equal to the energy you gained divided by the speed of light squared.  c² is a VERY big number so you need a lot of energy produced to notice it.  Chemical reactions are simply too inefficient to get that much energy out.
11)You need high temperatures for fusion because you're trying to push two atoms together (to "fuse" them as the name suggests)  The electrons in one atom repel the other electrons in the other atoms.  When stripped down to only protons, you still have to overcome this repulsion (Coulomb repulsion).  High temperatures means high velocity of the particles in the plasma.  This gives them enough "oomph" to get close enough to fuse.  Once close enough to each other, the nuclear force takes over and overwhelms the Coulomb repulsion and the nuclei fuse and release energy in doing so.
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Serga [27]
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4 0
3 years ago
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The velocity of the wave involved in the Doppler effect:
Margarita [4]

The Doppler Effect provides the equation for the calculation of apparent frequency:

f=fo[vo/(vo-vr)] 

where:<span>
vo=source wave velocity 
vr=relative speed between source and observer 
f=apparent frequency 
fo=source frequency </span>

<span>
The velocity of the doppler wave is 
v=λf</span>

where λ is light wavelength. Hence,

v=λfo[vo/(vo-vr)] 

Based on the equation, we can say that wave velocity will always be defined by one and only one wavelength.

Therefore the answer is letter C.

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4 0
3 years ago
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A man pushes a shopping cart across a level floor. What force resists the effort force? A) gravity B) friction C) the normal for
Kipish [7]

Answer:

B) Friction

Explanation:

Friction is a force that acts when an object is sliding along a surface. Microscopically, this force is due to the fact that the two surfaces are not perfectly smooth, but they have "imperfections" that cause a force that opposes the motion of the object.

For an object sliding on a flat surface, the force of friction has magnitude:

F_f = \mu_k mg

where

\mu_k is the coefficient of kinetic friction

m is the mass of the object

g is the acceleration of gravity

The direction of the force of friction is always opposite to the direction of motion of the object.

In reality, friction also acts if the object is at rest and it is pushed by a force; in this case, we talk about static friction, and its magnitude is

F_f = \mu_s mg

where \mu_s is called coefficient of static friction, and it is generally larger than the coefficient of kinetic friction.

8 0
3 years ago
7. A mother pushes her 9.5 kg baby in her 5kg baby carriage over the grass with a force of 110N @ an angle
jasenka [17]

Weight of the carriage =(m+M)g =142.1\ N

Normal force =Fsin(\theta) + W = 197.1\ N

Frictional force =\mu N=27.59\ N

Acceleration =4.66\ m\ s^{-2}

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

  • So Weight(W) =(m+M)\times g =(9.5+5)\ kg \times 9.8 =142.1\ Newton\ (N)

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with F_x, force of 110\ N acting vertically downward.Both are downward and Normal is upward so Normal force =Summation\ of\ both\ forces

  • Normal force (N) = Fsin(\theta)+W=110sin(30) + 142.1 =197.1\ N
  • Frictional force (f) =\mu N=0.14\times 197.1 =27.59\ N

To calculate acceleration we will use Newtons second law.

That is Force is product of mass and acceleration.

We can see in the diagram that F_y=Horizontal and F_x=Vertical component of forces.

So Fnet = Fy(Horizontal) - f(friction) = m\times a

  • Acceleration (a) =\frac{Fcos(\theta)-\mu N}{mass(m)} =\frac{(95.26-27.59)}{14.5}= 4.66\ m\ s{^2 }

So we have the weight of the carriage, normal force,frictional force and acceleration.

3 0
2 years ago
Explain why, under some circumstances, it is not advisable to weld a structure that is fabricated with a 3003 aluminum alloy. Hi
Scorpion4ik [409]

The 3003 aluminum alloy is made up of 1.25% Magnesium and 0.1% Copper. This combination is designed to increase the strength of the material over other types of alloys such as those of the 1000 series. This alloy provides a medium strength and can be educated by cold work.

The alloy is not heat treatable and generally has good formability, corrosion resistance and weldability.

However, being a material that hardens by cold work, welding a 3003 Aluminum structure will cause the body to undergo recrystallization which will generate a loss in the 'resistance' of the material and the force capable of withstanding. If this aluminum will be used for structural purposes, it should not be welded. It would be better to perform the structure with a 6061 aluminum, which has similar characteristics and is not so affected by welding.

7 0
3 years ago
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