(24xy^3-16x^2y^2+32x^2y)/8xy
<span><span>(<span><span><span><span><span><span><span>24x</span><span>y^3</span></span>−<span><span>16<span>x^2</span></span><span>y^2</span></span></span>+<span><span>32<span>x^2</span></span>y</span></span>8</span></span>x</span>)</span><span>(y)</span></span><span> =<span><span><span>−<span><span>2<span>x^3</span></span><span>y^3</span></span></span>+<span><span>3<span>x^2</span></span><span>y^4</span></span></span>+<span><span>4<span>x^3</span></span><span>y^<span>2</span></span></span></span></span>
Answer:
The point 
is not a solution of the system of inequalities
Step-by-step explanation:
we have
-----> inequality A
-----> inequality B
we know that
If a ordered pair is a solution of the system of inequalities
then
the ordered pair must be satisfy the inequalities of the system
Verify
For 
substitute the value of x and the value of y in the inequalkity A and in the inequality B
Inequality A
-------> is not true
therefore
The point is not a solution of the system of inequalities
If you would like to find the final score, you can do this using the following steps:
Team A: 6 points * 3 + 3 points * 2 + 2 points * 1 + 1 point * 0 = 6 * 3 + 3 * 2 + 2 * 1 + 1 * 0 = 18 + 6 + 2 + 0 = 26 points
Team B: 6 points * 4 + 3 points * 4 + 2 points * 1 + 1 point * 2 = 6 * 4 + 3 * 4 + 2 * 1 + 1 * 2 = 24 + 12 + 2 + 2 = 40 points
The final score of team A is 26 points and the final score of team B is 40 points.
