Answer:
The magnitude of the torque on the loop due to the magnetic field is .
Explanation:
Given that,
Diameter = 10 cm
Current = 0.20 A
Magnetic field = 0.30 T
Unit vector
We need to calculate the torque on the loop
Using formula of torque
Where, N = number of turns
A = area
I = current
B = magnetic field
Put the value into the formula
Hence, The magnitude of the torque on the loop due to the magnetic field is .
Answer:
3- A ball of mass 0,50 kg falls and hits the floor at 10m/s,
It rebounds at speed 8.0 m/s, as shown.
before collision
after collision
10 m/s
8 m/s
The collision between the ball and the floor lasts for 0.50 s.
What is the average force acting on the ball during the collision?
Answer:
<em>The internal energy change is 330.01 J</em>
Explanation:
Given
the initial volume = 5.75 L
the final volume = 1.23 L
is the external pressure = 1.00 atm
q the heat energy removed = -128 J (since is removed from the system)
expansion against a constant external pressure is an example of an irreversible pathway, here pressure in is greater than pressure out and can be obtained thus;
W = -ΔV
W = -1.00 x(1.23 - 5.75)
W = -1.00 x -4.52
W = 4.52 L atm
converting to joules we have
W = 4.52 L atm x 101.33 J/ L atm = 458.01 J
The internal energy change during compression can be calculated thus;
ΔU = q + W
ΔU = -128 J + 458.01 J
ΔU = 330.01 J
Therefore the internal energy change is 330.01 J
Answer: cause yes they can
Explanation:
How does u know
Answer:
The wind speed of the plane in still air is 50m/h
Explanation:
Let p = plane speed in the air
Let w = wind speed.
since , we can;
(Eqn1) can be simplified further into
In (Eqn2), multiply both sides with the reciprocal of which gives us
So we have;
p - w = 150
p + w = 250
2p = 400
p = 200
Put p (200) into p - w = 150;
200 - w = 150
w = 50
Therefore,
The speed of the plane in still air is 200m/h,
The wind speed is 50m/h.