Plug the x value which is 2 back to the x and solve.
I gave you two answers because I wasn’t sure if the question was (x^2) - 2 or x^2-2.
Those two functions look similar but is totally different so keep that in mind.
Hope you have a victorious day!
Answer:
Shows how to quickly check if a matrix product is defined and, if it is, how to ... You can use this fact to check quickly whether a given multiplication is defined.
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
the middle 50% wold be the numerical values in the actual box part of the box plot.
Answer:
Step-by-step explanation:
In order to find the value of n that satisfies this equation, we can perform a series of algebraic steps on it to solve for n.
- <em>Distribute in the 8 on the left side:</em>
- <em />
<em> </em> - <em>Add 4n to both sides</em>
- <em>Add 16 to both sides</em>
- <em>Divide both sides by 20</em>
Therefore, n=1 is the value of n that satisfies this equation.
Hope this helped!
Answer:
![\sqrt[]{\frac{x+8}{4}}-3](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7Bx%2B8%7D%7B4%7D%7D-3)
Step-by-step explanation:
First rewrite 
as y
Now swap y and x
Add 8 on both sides.
Divide by 4.
Extract the square root on both sides.
![\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7Bx%2B8%7D%7B4%7D%7D%3D%5Csqrt%5B%5D%7B%28y%2B3%29%5E2%7D)
![\sqrt[]{\frac{x+8}{4}}=y+3](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7Bx%2B8%7D%7B4%7D%7D%3Dy%2B3)
Subtract 3 on both sides.
![\sqrt[]{\frac{x+8}{4}}-3=y+3-3](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7Bx%2B8%7D%7B4%7D%7D-3%3Dy%2B3-3)
![\sqrt[]{\frac{x+8}{4}}-3=y](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7Bx%2B8%7D%7B4%7D%7D-3%3Dy)
