Hey there :)
Now lets name each house
A B C D E F
500ft <-> 500ft <-> 500ft <-> 500ft <-> 500ft <-> 2000ft
Let's say the bus stops at A
= 0 ( from A ) + 500 ( from B ) + 500 + 500 ( from C ) + 500 + 500 + 500 ( from D ) + 500 + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 500 + 2000 ( from F )
= 0 + 500 + 1000 + 1500 + 2000 + 4000
= 9000 ft
at B
= 500 ( from A ) + 0 ( from B ) + 500 ( from C ) + 500 + 500 ( from D ) + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 2000 ( from F )
= 500 + 0 + 500 + 1000 + 1500 + 3500
= 7000 ft
at C
= 500 ( from A ) + 500 + 500 ( from B ) + 0 ( from C ) + 500 ( from D ) + 500 + 500 ( from E ) + 500 + 500 + 2000 ( from F )
= 500 + 1000 + 0 + 500 + 1000 + 3000
= 6000 ft
Do the same for D , E and F
at D
= 6000 ft
at E
= 7000 ft
at F
= 15000 ft
You will find that the bus should stop at either C or D to make the sum of distances from every house to the stop as small as possible.
Answer:
Shortest Side = 20 feet
Second Side = 23 feets
Third Side = 37 feets
Step-by-step explanation:
Let the shortest side of the desk be x. Hence,
Second side = (x + 3) feets
Third side = (2x - 3) feets
Perimeter = 80ft
x + (x + 3) + (2x - 3) = 80
4x = 80
x = 20
Hence, Second side = (20 + 3) feets
= 23 feets
Third side = (40 - 3) feets
= 37 feets
Hence<u>,</u><u> shortest side is 20 feets, Second side is 23 feets, Third side is 37 feets.</u>
Answer:
no solution because the square root of a negative number is not a real number d=-100
Answer:



Can I have the brainliest please?
The correct option is option d
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