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Keith_Richards [23]
3 years ago
9

Describe what happens in a condensation reactions

Chemistry
1 answer:
dlinn [17]3 years ago
5 0
A condensation reaction is described to be a reaction wherein two molecules form an even larger product and consequently produces a smaller molecule as a by-product. For example, when two amino acids are combined, a dipeptide bond is formed. As a result, 1 molecule of water is produced as a by-product.
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At equilibrium at 2500K, [HCl]=0.0625M and [H2]=[Cl2]=0.00450M for the reaction H2+Cl2 ⇌ HCl.
ASHA 777 [7]

Answer:

a. H_2+Cl_2 \rightleftharpoons 2HCl

b. K = 192.9

c. Products are favored.

Explanation:

Hello!

a. In this case, according to the unbalanced chemical reaction we need to balance HCl as shown below:

H_2+Cl_2 \rightleftharpoons 2HCl

In order to reach 2 hydrogen and chlorine atoms at both sides.

b. Here, given the concentrations at equilibrium and the following equilibrium expression, we have:

K=\frac{[HCl]^2}{[H_2][Cl_2]}

Therefore, we plug in the data to obtain:

K=\frac{(0.0625)^2}{(0.00450)(0.00450)}\\\\K=192.9

c. Finally, we infer that since K>>1 the forward reaction towards products is favored.

Best regards!

8 0
3 years ago
DUE TOMORROW!!! 15 POINTS
Lunna [17]

Answer:

A. write balanced chemical equation (including states), for this process.

Explanation:

Almost all hydrocarbon 'burn' reactions involve oxygen; it's by far the most reactive substance in air.  

Hydrocarbon combustions always involve  

[some hydrocarbon] + oxygen --> carbon dioxide + steam.  

C6H6(l) + O2 (g)--> CO2 (g)+ H2O (g)

Balance carbon, six on each side:  

C6H6(l) + O2 (g)--> 6CO2 (g)+ H2O (g)

Balance hydrogen, six on each side:  

C6H6(l) + O2 (g)--> 6CO2(g) + 3H2O (g)

Now, we have fifteen oxygens on the right and O2 on the left.  

Two ways to deal with that. We can use a fraction:  

C6H6 (l)+ (15/2)O2 (g)--> 6CO2 (g)+ 3H2O (g)

Or, if you prefer to have whole number coefficients, double everything  

to get rid of the fraction:  

2C6H6 (l)+ 15O2 (g)--> 12CO2 (g)+ 6H2O (g)

With the SATP states thrown in...  

C6H6(l) + (15/2)O2(g) --> 6CO2(g) + 3H2O(g)

6 0
3 years ago
Which is a diatomic molecule?<br> A. Ar<br> B. CO<br> C. CO2<br> D. NaCl
aleksley [76]
NaCI is the answer, in what my teacher taught me. Hope I helped :)
5 0
3 years ago
Organic chemistry involves which type of study?
Mariulka [41]

Answer: option A

Explanation: Organic chemistry deals with the study of carbon and hydrogen containing compounds, drugs and pharmaceuticals etc.

7 0
3 years ago
1.20 x 10^22 molecules NaOH to gram
Trava [24]

Answer:

\boxed {\boxed {\sf 0.797 \ g \ NaOH}}

Explanation:

<u>1. Convert Molecules to Moles</u>

First, we must convert molecules to moles using Avogadro's Number: 6.022*10²³. This tells us the number of particles in 1 mole of a substance. In this case, the particles are molecules of sodium hydroxide.

\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}

Multiply by the given number of molecules.

1.20*10^{22} \ molecules \ NaOH *\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}

Flip the fraction so the molecules cancel out.

1.20*10^{22} \ molecules \ NaOH *\frac {1 \ mol \ NaOH} {6.022*10^{23} \ molecules \ NaOH}}

1.20*10^{22}  *\frac {1 \ mol \ NaOH} {6.022*10^{23}}}

\frac {1.20*10^{22} \ mol \ NaOH} {6.022*10^{23}}}

0.0199269345732 \ mol \ NaOH

<u>2. Convert Moles to Grams</u>

Next, we convert moles to grams using the molar mass.

We must calculate the molar mass using the values on the Periodic Table. Look up each individual element.

  • Na: 22.9897693 g/mol
  • O: 15.999 g/mol
  • H: 1.008 g/mol

Since the formula has no subscripts, we can simply add the molar masses.

  • NaOH: 22.9897693+15.999+1.008=39.9967693 g/mol

Use this as a ratio.

\frac {39.9967693 \ g  \ NaOH }{1 \ mol \ NaOH}

Multiply by the number of moles we calculated.

0.0199269345732 \ mol \ NaOH*\frac {39.9967693 \ g  \ NaOH }{1 \ mol \ NaOH}

The moles of sodium hydroxide cancel.

0.0199269345732 *\frac {39.9967693 \ g  \ NaOH }{1}

0.0199269345732 *39.9967693 \ g  \ NaOH

0.79701300498 \ g \ NaOH

The original measurement of molecules has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 0 tells us to leave the 7 in the hundredth place.

0.797 \ g \ NaOH

1.20*10²² molecules of sodium hydroxide is approximately 0.797 grams.

4 0
3 years ago
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