X=3y+4, y=y
x+y=180, 3y+4+y=180, 4y+4=180
4y+4=180
4y=176
y=44
x=3(44)+4, x=132+4, x=136
(I am not a very good artist in this case:)
Answer:
24hours
Step-by-step explanation:
let Evan be x, Tyler=x-12,equate;1/x+1/(x-12)=1/8,to get x=24 or 4.The correct value of x=24 because if you take x=4 means that Tyler=-8hours which is impossible
Answer:
A) 9 photos in each row
B) 14 rows in total
Step-by-step explanation:
Photos of People = 45
Photos of Landscapes = 18
Photos of Pets = 63
Jenny wants to arrange these photos in rows with only one kind of photos in each row and same number of photos in each row. We have to find the greatest possible number of photos in each row. For this we need to find the greatest common factor of 45,18 and 63. This would give us the greatest possible number of photos that can be placed in each row.
By observing the 3 numbers, we can tell that the greatest common factor of these 3 numbers is 9. So, Jenny can place 9 photos in each row.
So,
There will be:
45/9 = 5 rows with photos of people
18/9 = 2 rows of photos of landscapes
63/9 = 7 rows of photos of pets
So, total number of rows would be = 5 + 2 + 7 = 14 rows
Answer:
5cm
Step-by-step explanation:
Given area of trapezium = 31.5 sq. cm
Length of parallel sides = 7.3cm and 5.3cm
Formula to calculate area of trapezium is
1/2*(sum of parallel sides)*perpendicular distance between parallel sides
sum of parallel sides = (7.3 + 5.3) = 12.6cm
substituting value of area given and sum of parallel sides we have
31.5 = 1/2* 12.6 * perpendicular distance between parallel sides
(31.5 * 2)/12.6 = perpendicular distance between parallel sides
perpendicular distance between parallel sides = 63/12.6 = 5
Therefore perpendicular distance between parallel sides for given trapezium is 5cm.
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section. That's
(change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.