Answer:
The power dissipated in either one of the parallel resistors is 2 V
Explanation:
Given;
two parallel resistors, R₁ and R₂ = 2 ohms
The total resistance of the Two resistors of 2 ohms connected in parallel is;
when connected to another resistor of 1 ohm in series, the total resistance becomes;
Rt = R₁ + R₂
Rt = 1 + 1 = 2 ohms
Current in the circuit, I = voltage / total resistance
= 2 /2 = 1 A
the overall circuit has been resolved to series connection, and current flow in series circuit is constant.
Power = I²R
Thus, power dissipated in either one of the parallel 2 ohms resistors is;
Power = I²R = (1)² x 2 = 2 V
4 for sure because you dont want anything spilling on you or others that is harmful.
1) nuclear fusion
During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. During this process, radiant energy is released.
<span>.Ask a Question
.Do Background Research.
.Construct a Hypothesis.
.Test Your Hypothesis by Doing an Experiment
.Analyze Your Data and Draw a Conclusion.
<span>.Communicate Your Results.</span></span>
<span>a = (v2 - v1)/t= acceleration formula
a = (70 - 0)/7
a = 10 km/hr/sec
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It's better to use as few units as possible.
10 km/hr = 10 km*1000 m/km/(1 hr*3600 sec/hr) = 25/9 m/sec
a= 25/9 m/sec/se</span>