Explanation:
It is given that,
Velocity of the electron, 
Magnetic field, 
Charge of electron, 
(a) Let 
is the force on the electron due to the magnetic field. The magnetic force acting on it is given by :
![F_e=1.6\times 10^{-19}\times [(2\times 10^6i+3\times 10^6j)\times (0.030i-0.15j)]](https://tex.z-dn.net/?f=F_e%3D1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%20%5B%282%5Ctimes%2010%5E6i%2B3%5Ctimes%2010%5E6j%29%5Ctimes%20%280.030i-0.15j%29%5D)
(b) The charge of electron, 
The force acting on the proton is same as force on electron but in opposite direction i.e (-k). Hence, this is the required solution.
Type of image is either real or virtual.
Real images (convex)
-light rays travel to a real image from the object
Virtual images (concave)
-not really there and no light reaches them
d. type of light source
**just an opinion, i might be incorrect
The energy of a photon is given by
where h is the Planck constant and f is the frequency of the light.
Given the relationship between the frequency f, the wavelength
and the speed of light c for an electromagnetic wave:
we can rewrite the energy of the photon as
and by substituting
,
and
, we get the wavelength of the photon:
Answer:
Follows are the solution to this question:
Explanation:
In point a:
Place of particles
In point b:
when 
the Particle velocity 
In point c:
Calculating the Particle acceleration:
