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Gemiola [76]
2 years ago
9

Please help stuck on question

Mathematics
1 answer:
vazorg [7]2 years ago
5 0

Answer:

Suppose we have a polynomial of degree N with a leading coefficient A and roots {x₁, x₂, ..., xₙ}

We can write this polynomial as:

P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

such that the terms:

(x - x₁), (x - x₂), etc...

are called the factors.

In this case, we know that the roots OF THE FACTORS

are:

(x = - 2)

(x = - (1 + √5))

(x = + 3i)

If the root of the polynomial is  x = -2, then the factor should be:

(x + 2)

which is zero when we evaluate x in -2

Then the correct option is the first one.

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A number squared divided by 2 and added to 16
nadya68 [22]

Answer:

Suppose the number is 4

Square of this number (4 x 4 ) = 16

Divided by 2 = 16/2 = 8

Added to 16 = 8+16 = 24

Step-by-step explanation:

4 0
3 years ago
How many 2 digit numbers can be formed using 9,2,6,4,8,5,7 without repetition​
-BARSIC- [3]

There are 7 numbers.

Each number can be paired with the remaining 6 numbers.

7 x 6 = 42 different two digit numbers can be made.

5 0
3 years ago
Which equation is represented by the graph below?
aleksandr82 [10.1K]
The are you have selected
5 0
3 years ago
What is (g•f)(2). ?
Leona [35]
G(F(2))
So f would be x
-(2x+1)-2 you slove it and get you answer and plug the answer back into the equation above as x
-(2(answer)+1)-2
Hope this helps
5 0
3 years ago
How do you answer this <br> -4(2+3)-4(5-4)
FrozenT [24]

Answer:

if ur simplifying its -24

−4(2+3)−4(5−4)

=(−4)(5)−4(5−4)

=−20−4(5−4)

=−20−(4)(1)

=−20−4

=−24

5 0
3 years ago
Read 2 more answers
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