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Gemiola [76]
2 years ago
9

Please help stuck on question

Mathematics
1 answer:
vazorg [7]2 years ago
5 0

Answer:

Suppose we have a polynomial of degree N with a leading coefficient A and roots {x₁, x₂, ..., xₙ}

We can write this polynomial as:

P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

such that the terms:

(x - x₁), (x - x₂), etc...

are called the factors.

In this case, we know that the roots OF THE FACTORS

are:

(x = - 2)

(x = - (1 + √5))

(x = + 3i)

If the root of the polynomial is  x = -2, then the factor should be:

(x + 2)

which is zero when we evaluate x in -2

Then the correct option is the first one.

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3y-y+8-2=20<br> combine like terms and solve
Flauer [41]
3y - y + 8 - 2 = 20
3y - y = 2y
8 - 2 = 6
2y + 6 = 20
2y = 20 - 6
y = 10 - 3
the answer is: y = 7
4 0
3 years ago
The product of two exponentail expressionss is x5 y2 z. One of the expressions is x2 y. What is the other expression?
Yakvenalex [24]
I hope this helps you



x^5.y^2.z/x^2.y


x^5-2.y^2-1.z


x^3.y.z
8 0
3 years ago
Read 2 more answers
Help me with this attachment please?
Volgvan

<u>Answer</u>

1st solution: a = 1

                   b = 3

2nd solution: a = 2

                      b = 6


<u>Explanation</u>

1st solution

                  <em>         1</em>

<em>                       333</em>

<em>                       333</em>

<em>                       333</em>

<em>                   </em><em><u>  +333</u></em>

<em>               </em><em><u>       1333</u></em>

2nd solution

<em>         2</em>

<em>    666</em>

<em>    666</em>

<em>    666</em>

<em><u> + 666</u></em>

<em><u> 2666</u></em>

4 0
3 years ago
Read 2 more answers
Use row operations to solve the system.
Aleks04 [339]

Answer:

x = 2, y = 7, z = 12

Step-by-step explanation:

x + y - z = -3 (1)

3x - y + z = 11 (2)

x - 4y + z = -14 (3)

add (1) and (2)

4x = 8 x = 2

add (1) and (3)

2x - 3y = -17

2(2) - 3y = -17

-3y = -17 - 4

-3y = -21

y = 7

Find z using any equation

x + y - z = -3

2 + 7 - z = -3

9 - z = -3

z = 12

3 0
3 years ago
Anybody got an answer?
Anna11 [10]
For a regular n-agon with side length "s" and apothem "h", the area will be
.. A = n*(1/2)*s*h
Your area is
.. A = 10*(1/2)*(3.25 m)*(5 m) ≈ 81.3 m^2
8 0
3 years ago
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