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pav-90 [236]
3 years ago
8

(8) can you please help me with my math!

Mathematics
1 answer:
Talja [164]3 years ago
7 0

Answer:

776

Step-by-step explanation:

98999

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A Circular pie with a diameter of 10” Is cut into six equal pieces. What is the surface area of two slices of pie?
-Dominant- [34]

To solve this question, let's find the surface area of the entire pie and then divide it by 6 for each slice.

The area of a circle is pi*r^2. We are given the diameter, so divide that by 2 to get the radius.



Now that you have the area, divide by 6. That is the area of each slice. The problem asks for the area of 2 slices though, so multiply that by 2.

4 0
2 years ago
An electrician cuts a 136 foot long piece of cable. One piece is 16 feet less than 3 times the length of the other piece. Find t
Ugo [173]

Answer:

98 ft  and   38 ft

Step-by-step explanation:

We know that the initial length of the piece is  136 feet

Then the piece is cut into two pieces.

Let's call x the length of the first piece  of cable and call z the length of the second piece of cable.

So we know that

x + z = 136

and

x = 3z-16

Now we substitute the second equation in the first one and solve for the variable z

3z-16 + z = 136

4z-16= 136

4z= 136+16

z= \frac{152}{4}

z=38\ ft

Now we find the length x

x + 38 = 136

x= 136-38

x= 98\ ft

7 0
4 years ago
I WILL GIVE THE BRAINLIEST PLEASE HELP ASAP
guapka [62]

Answer:

Account 1:

3(2500 × 4/100) = 300

Account 2,

2500(1.035)³ - 2500 = 271.7946875

Slightly surprised because the riskier one should yield higher gain

3 0
3 years ago
Read 2 more answers
What are the prime factors of 3025?
mr_godi [17]
3025|5\to(3025:5=605)\\.\ 605|5\to(605:5=121)\\.\ 121|11\to(121:11=11)\\.\ \ 11|11\to(11:11=1)\\.\ \ \ 1|\\\\3025=5\ \times\ 5\ \times\ 11\ \times\ 11
4 0
3 years ago
Read 2 more answers
emma is planning a surprise party. She is considering using one of two venues. The banquet of hall A will cost $862 fot a reserv
mylen [45]
Ok for this problem, there are 2 equations representing hall A and hall B

hall A:  y=76x+862 where x=number of dinners and y=total cost

hall B:  y=75x+894 for the same variables

To find where the 2 meet, simply substitute one equation into the other, creating:  76x+862=75x+894

Solving this, we find that x=32, so at 32 guests, the cost would be the same

For part 2, put the answer for part 1 into either equation from the start, so y=76(32)+862, or y=3294

And we already found that x=32, which represents the # of guests
4 0
3 years ago
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