Answer:
260?
Step-by-step explanation:
I used the equation (4)13+(16)13 and plugged it into my calculator and got 260.
The point on the y axis is y=6/5–5
Answer:
Option a is the correct answer.
Step-by-step explanation:
Let x,y and z represent the marks scored in first,second and third tests respectively.
Total score is 239, then:
x+y+z = 239 -------1
Combined scores of first and second tests is 59 more than that of third test,then:
x+y = 59+z
x+y-z = 59 ---------2
The score of second test is 25 more than that of third test, then:
y = 25+z
0x+y-z = 25 --------3
The matrix equation for this situation is:
.
Answer:360/90 = 4
Total area = 4 times that of the sector.
Step-by-step explanation:
A 90 deg sector has 1/4 the area of the circle.
Total circle area = 4*9pi = 36pi
Answer:
Check the explanation
Step-by-step explanation:
One way ANOVA
The null and alternative hypothesis for this one way ANOVA is given as below:
Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.
Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.
The ANOVA table with calculations can be seen in the attached images below:
In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.
In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.