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Genrish500 [490]
3 years ago
13

Find the length of side a

Mathematics
1 answer:
avanturin [10]3 years ago
4 0

Answer:

Wheres the picture

Step-by-step explanation:

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SOMEONE ANYONE PLEASE...SMART ANSWER?​
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A triangle needs a total of 180° to be a complete triangle. First let's solve for m∠B since we have the other angles given in that triangle.

30 + 70 = 100

180 - 100 = 80° still needed to form a complete triangle. This is what m∠B equals.

From the image provided, we can see that both triangles are the exact same. So all we need to do now is find the angle that matches m∠B. In this case that angle is m∠D. Knowing that m∠B = 80° the final answer is:

m∠D = 80°

Hoped This Helped! Good Luck!

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2 years ago
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Shelly made 5 more sales calls than Clark . Shelly and Clark made a total of 33 sales calls . How many sales calls did each make
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S = 5 + C
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Help please!!!!!!!!!
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ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

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3 years ago
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