Answer:
84.00g CO2 * 1mol CO2/44.009g CO2 * 25mol O2/16mol CO2 * 31.998g O2/1mol O2 = 95.43g O2
Explanation:
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CH₃C≡CH + 2Br₂ → CH₃CBr₂CHBr₂
Answer:
Explanation:
Structure of the 2,2,4,4-tetramethyl-3-pentanone is give in the attachment
In 2,2,4,4-tetramethyl-3-pentanone, no alpha hydrogen is present, therefore, enol form is not possible and hence, exist only in keto form.
Explanation for existence of cyclohexa-2,4-diene-1-one only in enol form:
keto form of cyclohexa-2,4-diene-1-one not aromatic and hence less stable.
Whereas enol form it is aromatic which makes it highly stable. that's why cyclohexa-2,4-diene-1-one exists only in enol form.
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