Answer:
pH = 6.8124
Explanation:
We know pH decreases with increase in temperature.
At room temperature i.e. 25⁰c pH of pure water is equal to 7
We know
Kw = [H⁺][OH⁻]...............(1)
where Kw = water dissociation constant
At equilibrium [H⁺] = [OH⁻]
So at 37⁰c i.e body temperature Kw = 2.4 × 10⁻¹⁴
From equation (1)
[H⁺]² = 2.4 × 10⁻¹⁴
[H⁺] = √2.4 × 10⁻¹⁴
[H⁺] = 1.54 × 10⁻⁷
pH = - log[H⁺]
= - log{1.54 × 10⁻⁷}
= 6.812
Answer:
Magnitude
Explanation:
Astronomers define star brightness in terms of magnitude (how bright the star appears from Earth)
The overall balanced reaction equation is;
4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)
<h3>What is the balanced reaction equation?</h3>
The redox reaction equation is said to be balanced when the number of electron gained is equal to the number of electrons lost.
Now;
1. Reduction and oxidation half-reactions
Zn(s) -----> Zn^2+(aq) + 2e
And
NO3^-(aq) ---->NH4^+(aq) + 3H2O(l)
2. Using the H2O and H+ to balance O and H;
4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)
3. Balancing the electrons lost and gained; 4Zn(s) + 10H^+(aq) + NO3^-(aq) + 8e -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l) + 8e
4. The overall balanced reaction equation is;
4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)
Learn more about redox reaction:brainly.com/question/13293425
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<u>Answer:
</u>
Reaction C
<u>Explanation:
</u>
For reaction A) we have the production of alcohol by the action of the water that attacks the tertiary carbocation produced by the leaving of Br. In the last step we will have the proton transfer (figure 1).
For B) the proton transfer step is given in the double bond formation due to the attack of the hydroxle group (figure 2).
In C we have an Sn2 reaction. Therefore, the reaction takes place in only one step without the opportunity of a proton transfer step (figure 3).
Finally for D we have an elimination reaction in which the tert-butoxide molecule will remove hydrogen (proton transfer step) from the carbocation to produce an alkene (figure 4).
