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Radda [10]
2 years ago
12

5. Circle the letter of any card that gives an example of like terms. A. 1\4c and -9c. B. 2.2n and 2.2. C. 6y and 6x. D. 5d^2 an

d d^2. E. 30 and -25.​
Mathematics
1 answer:
kolezko [41]2 years ago
6 0

Answer: D

Step-by-step explanation: 5d^2 and d^2 share the same variable

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-1/2 + (3/4 x 4/9) =
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What is the maximum value that the graph of y = cos x assumes?
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Read 2 more answers
Theequationforlinegcanbewrittenas y = –9 4 x − 1 . Line h , whichisperpendiculartoline g , includesthepoint (10, 4) . What isthe
KATRIN_1 [288]

Answer:

y-4 = 4/9(x-10)

Step-by-step explanation:

Given the equation of the line g to be y = -9/4 x - 1.

To find the equation of a line h perpendicular to this line, the following steps must be taken;

First find the slope of the known line g

The standard equation of a line is y = mx+c where

m is the slope

c is the intercept

Comparing this equation with the given equation y = -9/4 x -1, it can be seen that the slope of the line g is -9/4

Next is to find the slope of the line h

Since the line g is perpendicular to h, then the product of their slope will be -1 i.e mh*mg = -1

mh = -1.mg

mh = -1/(-9/4)

mh = -1*-4/9

mh = 4/9

Hence the slope of the line h is 4/9

Find the intercept of line h

To get this, you will substitute the slope m and the point into the equation y = mx+c

m = 4/9

(x,y) = (10,4)

4 = 4/9(10) + c

4 = 40/9 + c

c = 4-40/9

c = (36-40)/9

c = -4/9

Hence the intercept of the line h is -4/9

Finally, find the equation of the line h in slope-intercept form

The slope-intercept form of a line is expressed as y = mx+c

y-y0 = m(x-x0)

Given

m = -4/9

x0 = 10

y0 = 4

Substitute:

y-4 = 4/9(x-10)

Hence the equation in slope-intercept form is y-4 = 4/9(x-10)

7 0
3 years ago
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