6. aa and cc ; two lower-case letters indicate the expression of a recessive trait because there is no dominant trait to mask it. (Dominant alleles are capitalized).
7. 1 pp (lower case = recessive)
7.2 Pp, PP; because the white flower is pp, the flower's recessive trait is white. White will only be expressed in the absence of a P, the dominant gene. If a P is in the genotype, it will mask the p allele' causing the flower to be purple.
Answer:
Answer: The correct answer is Option B.
Explanation:
To calculate the number of moles, we use the equation:
\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}Number of moles=Molar massGiven mass ....(1)
For N_2N2 :
Given mass of nitrogen gas = 10 g
Molar mass of nitrogen gas = 28 g/mol
Putting values in above equation, we get:
\text{Moles of iron oxide}=\frac{10g}{28g/mol}=0.357molMoles of iron oxide=28g/mol10g=0.357mol
The given chemical reaction follows:
N_2+O_2\rightarrow 2NON2+O2→2NO
As, oxygen gas is present in excess. Thus, it is considered as an excess reagent and nitrogen is considered as a limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
Answer:
The number ofcarbon atoms in ethanol is 2 and it is 6 in sugar.
Hydrogen atoms is 6 in ethanol and 12 in sugar
Oxygen is 1 atom in ethanol and 6 atoms in sugar.
Explanation:
All these account for them as two different compounds.
Answer:
The concentration of CH₃OH in equilibrium is [CH₃OH] = <em>2,8x10⁻¹ M</em>
Explanation:
For the equilibrium:
CO (g) + 2H₂(g) ⇄ CH₃OH(g) keq= 14,5
Thus:
14,5 =
In equilibrium, as [CO] is 0,15M and [H₂] is 0,36M:
14,5 =
Solving, the concentration of CH₃OH in equilibrium is:
<em>[CH₃OH] = 0,28M ≡ 2,8x10⁻¹ M</em>
I hope it helps!
Answer:
K = [HI]² / [H₂] [I₂]
Explanation:
To write the expression of equilibrium constant, K, it is important that we know how to obtain the equilibrium constant.
The equilibrium constant, K for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient. Thus, the equilibrium constant is written as follow:
K = [Product] / [Reactant]
Now, we shall determine the equilibrium constant for the reaction given in the question above. This can be obtained as illustrated below:
H₂(g) + I₂(g) —> 2HI (g)
K = [HI]² / [H₂] [I₂]