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2 years ago

What type of reaction is the transformation of oxalacetic acid into malic acid?

Chemistry

1 answer:

andrew-mc [135]2 years ago

4 0

$NADP{{H}_{2}}$ is required for the transformation of oxaloacetic acid into malic acid.

<h3>What is malic acid?</h3>

Malic acid is sour and acidic. This helps to clear away dead skin cells when applied to the skin.

The conversion of oxaloacetic acid into malic acid takes place in $C_4$ plants through the $C_4$ cycle by the process of photosynthesis.

Carboxylation of pyruvate produces oxaloacetate (OAA). This is an energy-requiring reaction that uses adenosine triphosphate (ATP).

Hence, $NADP{{H}_{2}}$ is required for the transformation of oxaloacetic acid into malic acid.

Learn more about malic acid here:

brainly.com/question/13460789

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3 years ago

A sample of a compound is determined to have 1.17 g of carbon and 0.287 g of hydrogen. what is the correct representation of the

yarga [219]

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

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5 0

2 years ago

How many liters is 3.3 moles of a gas?

andrezito [222]

Answer:

224.1

Explanation:

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3 years ago

Power plants release sulfur dioxide and nitrogen oxides into the atmosphere, where they combine with water vapor to form _____ p

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3 years ago

Read 2 more answers

1.2 kg of aluminum at 20oC is added to 1.5 kg of water at 80oC. After the system reaches thermal equilibrium, what is its final

Lubov Fominskaja [6]

Answer:

The final temperature is 71.19 °C

Explanation:

Step 1: Data given

Mass of aluminium = 1.2 kg = 1200 grams

Temperature of aluminium = 20.0 °C

Specific heat of aluminium = 0.900 J/g°C

Mass of water = 1.5 kg = 1500 grams

Temperature of water = 80.0 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the final temperature

heat gained = heat lost

Q(aluminium) = - Q(water)

Q = m*c*ΔT

m(aluminium) * c(aluminium) * ΔT(aluminium) = - m(water) * c(water) * ΔT(water)

⇒ with mass of aluminium = 1200 grams

⇒ with specific heat of aluminium = 0.900 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 20.0 °C

⇒ with mass of water = 1500 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 80.0°C

1200 * 0.900 * (T2-20.0°C) = -1500 * 4.184 * (T2 - 80.0°C)

1080 * (T2 - 20.0°C) = -6276 * (T2 - 80.0°C)

1080 T2 - 21600 = -6276T2 + 502080

7356T2 = 523680

T2 = 71.19 °C

The final temperature is 71.19 °C

8 0

3 years ago