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FromTheMoon [43]
4 years ago
7

Predict the color of the flame for the compound sodium hydroxide, naoh. explain your reasoning.

Chemistry
1 answer:
Lemur [1.5K]4 years ago
6 0
I would predict the color to be yellow-orange because the first element in the formula, and
also the metal, is sodium and therefore would fall under the other sodium formulas that
<span>produced a yellow-orange color.</span>
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What is the ratio? <br> A 3:1<br> B 2:1<br> C 21:7
Stolb23 [73]

Answer:

I think it's b if not then sorry

3 0
3 years ago
4.0 mol Na2S reacts with 5.0 mol
Bumek [7]

The number of moles of Na_2SO_4 form from 5.0 moles Na_2S is 5 moles.

<h3>What is a limiting reactant?</h3>

Limiting reactants are those reactants that are completely used up in a chemical reaction.

4.0 mol Na_2S will be completely used since the combining ratio is 1 : 1 : 1.

Na_2S + CuSO_4 ->Na_2SO_4 + CuS

From the chemical equation above, 5.0 moles Na_2S will yield 5 moles of Na_2SO_4.

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5 0
2 years ago
Electrolyte solutions conduct electricity because electrons are moving through the solution. true or false g
Rasek [7]

Answer: False

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7 0
3 years ago
Cual es el calor específico de una sustancia que tiene una masa de 15 g y una capacidad térmica de 0.550 calC
mr Goodwill [35]

Answer:

Explanation:

Q = Ce . m .ΔT

Q : calor  

Ce : calor especifico

m: masa  

ΔT : variación de temperatura

capacidad térmica : 0,550 cal / °C

lectura :

por 1 °C se tiene 0,550 cal

por lo tanto  tenemos datos de la temperatura y del calor

pero no olvidar las unidades en el sistema internacional :

Ce : J / kg . K

J: joules

kg: kilogramo

K: kelvin  

pasar de gramos a kilogramos

pasar de calorías a joules

pasar de grado celsius a kelvin

1000g equivale a 1kg

15g     equivale a 0,015 kg

K= °C + 273 ⇒ formula para pasar de grado celsius a kelvin

K=  1 + 273

K= 274

1 caloría equivale a  4,184 joules

0,550 caloría  equivale a 2,3012 joules

ahora como todos los datos ya están en el S.I remplazamos en la formula

Q = Ce . m .ΔT

2,3012 = Ce . 0,015.274

Ce=0,5599 J / kg. K

6 0
3 years ago
Calculate the heat change in calories for vaporization of 30.0g of water at 100degrees C
Levart [38]

Answer:

1.62 × 10⁴ cal

Explanation:

Step 1: Given and required data

  • Mass of water (m): 30.0 g
  • Latent heat of vaporization of water (ΔH°vap): 540 cal/g

Step 2: Calculate the heat change (Q) for vaporization of 30.0g of water at 100 °C

The vaporization is a phase change in which water passes from the liquid state to the gaseous state. We can calculate the heat required using the following expression.

Q = ΔH°vap × m

Q = 540 cal/g × 30.0 g

Q = 1.62 × 10⁴ cal

3 0
3 years ago
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