All points to the of zero on a horizontal number line are negative
2 answers:
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The wavelength of the third line in the Lyman series, and identify the type of EM radiation
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.
1 / lambda = R(h)* ( -
)
= 109678 ( -
)
= 109678 (8/9)
Lambda = 9 / (109678 * 8 )
= 102.6 * m = 102.6 nm
To learn more about Lyman series here
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