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Ghella [55]
2 years ago
15

If you stood on mars and lifted a 15kg pack, you would be pulling with a force greater than...?

Physics
1 answer:
DIA [1.3K]2 years ago
7 0

Answer:

See the answers below

Explanation:

In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

W=m*g

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

<u>Mercury</u>

<u />w_{mercury} = 15*3.8\\w_{mercury}= 57 [N]\\<u />

<u>Venus</u>

<u />w_{venus}=15*8.8\\w_{venus}= 132 [N]<u />

<u>Moon</u>

<u />w_{moon}=15*1.6\\w_{moon}=24[N]<u />

<u>Mars</u>

w_{mars}=15*3.7\\w_{mars}=55.5 [N]

<u>Jupiter</u>

<u />w_{jupiter}=15*23.1\\w_{jupiter}= 346.5[N]<u />

<u>Saturn</u>

<u />w_{saturn}=15*9\\w_{saturn}=135[N]<u />

<u>Uranus</u>

<u />w_{uranus}=15*8.7\\w_{uranus}=130.5[N]<u />

<u>Neptune</u>

<u />w_{neptune}=15*11\\w_{neptune}=165[N]<u />

<u>Pluto</u>

<u />w_{pluto}=15*0.6\\w_{pluto}=9[N]<u />

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An electron that has a velocity with x component 2.6 × 106 m/s and y component 3.2 × 106 m/s moves through a uniform magnetic fi
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The magnetic force is:

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