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3 years ago

Is x^2 a quadratic expression?

Mathematics

2 answers:

givi [52]3 years ago

5 0

Yes it is a quadratic expression

kotykmax [81]3 years ago

4 0

I think it should be so yes

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Use the functions f(x) and g(x) to answer the question. F(x)=x²-16; g(x)=x+4

AnnZ [28]

(x^2) - 16 / x+4 = (x-4)(x+4) / (x+4) = x-4, x not equal to -4

D is the answer.

7 0

3 years ago

- 3 (n-3)-5<br> simplify the expression using distributive property please rnnn

Tju [1.3M]

Distribute the “-3” to both n&-3 —> -3n+9 then your left with -5 and subtract 9-5

-3n+4

Hope this helps:)

4 0

3 years ago

Find the measure of two supplementary angles, ∠A and ∠B, if m∠A = (3x – 7)° and m∠B = (2x + 2)°. =180

nikklg [1K]

Answers:

Angle A = 104 degrees

Angle B = 76 degrees

=================================

Supplementary angles add to 180 degrees.

A+B = 180

(3x-7)+(2x+2) = 180

5x-5 = 180

5x-5+5 = 180+5 ... add 5 to both sides

5x = 185

5x/5 = 185/5 .... divide both sides by 5

x = 37

Use x =37 to find

Angle A = 3x-7 = 3*37-7 = 111-7 = 104 degrees

Angle B = 2x+2 = 2*37+2 = 74+2 = 76 degrees

As a check: A+B = 104+76 = 180 so that helps confirm the answer

4 0

3 years ago

Which expression is equivalent to (x – 1)7?

aleksley [76]

Hello!

The answer is B

Hope this helps!

6 0

3 years ago

When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra

Sergeu [11.5K]

Answer:

$r=\sqrt{10}\text{ m}$

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

$V=\pi r^2h$ , where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be $h = 0.7$ meters at $V=22\text{ m}^3$ .

Upon substituting these values in above formula, we will get:

$22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})$

$22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}$

$\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2$

$r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}$

$r^2=10\text{ m}^2$

Now, we will take positive square root of both sides as radius cannot be negative.

$\sqrt{r^2}=\sqrt{10\text{ m}^2}$

$r=\sqrt{10}\text{ m}$

Therefore, radius of tank would be approximately square root of 10 m.

5 0

3 years ago