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MA_775_DIABLO [31]
3 years ago
5

Weight (g)

Mathematics
1 answer:
navik [9.2K]3 years ago
5 0

Answer:  a) add n+1 to the previous term

               b) add the previous two terms

               d) subtract n+1 from the previous term

               e) multiply the previous term by 3

               f) subtract 2 from previous term then add 5 to the next term

<u>Step-by-step explanation:</u>

a) 1, 3, 6, 10

    ∨  ∨  ∨

  +2 +3 +4           The next term is 10 +5 = 15

b) 1, 2, 3, 5

    ∨  ∨  ∨

  =3 =5 =8        The next term is 5 + 8 = 13

d)  8, 7, 5, 2

      ∨  ∨  ∨

     -1  -2  -3             zThe next term is 2 - 4 = -2

e) 1, 3, 9, 27

     ∨  ∨  ∨

    ×3 ×3 ×3         The next term is 27 × 3 = 81

f) 49, 47, 52, 50, 55

      ∨    ∨    ∨    ∨

     -2   +5   -2   +5      The next term is 55 - 2 = 53

                                    The following term is 53 + 5 = 58

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Answer:

The answer is D

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K(2, 7), L(6, 12), M(13, 13), N(9.8) (Slope Formula) is it a parallelogram?
vredina [299]

angles and sides opposite one another on a parallelogram are congruent, we can say this is a parallelogram because there are congruent.

What in mathematics is a parallelogram?

  • A quadrilateral with the opposing sides parallel is called a parallelogram (and therefore opposite angles equal).
  • A parallelogram with all right angles is known as a rectangle, and a quadrilateral with equal sides is known as a rhombus.

Slope Formula: y2-y1/x2-x1

KL: 12-7/6-2 = 5/4

LM; 13-12/13-6 = 1/7

MN: 8-13/9-13 = 5/4

KN: 7-8/9-2 = 1/7

Since angles and sides opposite one another on a parallelogram are congruent, we can say this is a parallelogram because there are congruent.

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8 0
1 year ago
In 2012 your car was worth $10,000. In 2014 your car was worth $8,800. Suppose the value of your car decreased at a constant rat
Sonbull [250]

Answer:

g(t) = 10000(0.938)^t

Step-by-step explanation:

Given data:

car worth is $10,000 in 2012

car worth is $8000 in 2014

let linear function is given as

P(t) = at + b

which denote the value of car in year t

take t =0 for year 2012

at t =0, 10,000 = 0 + b

we get b = 10,000

take t =2 for year 2014

at t =2, P(2) = 2a + b

8800 = 2a + 10,000

a = - 600

Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000

let the exponential function p(t)  =ab^2 where t denote t = 0 at 2012

putting t = 0 P(0) = 10,000 we get 10,000 = ab^0

a = 10,000

putting t = 2 p = 8800

8800 =ab^2

b^2 = \frac{8800}{10000}

b = 0.938

g(t) = 10000(0.938)^t

3 0
3 years ago
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