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mrs_skeptik [129]
3 years ago
12

Expand and simplify (x-3)(x+5)

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

^2 + 2x-15

Hope this helps

elixir [45]3 years ago
5 0
How to solve your problem
(

−
3
)
(

+
5
)
Simplify
1
Distribute
(

−
3
)
(

+
5
)

(

+
5
)
−
3
(

+
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ANSWER FAST PLEASE!!!! 
zheka24 [161]

The area of the given trapezoid will be the sum of the areas of the triangular part and the rectangular part.

Now, the area of the rectangle, A_1 is:

A_1=length \times width=2\times 1.5=3 squared yards

Likewise, the area, A_2 of the triangle will be:

A_2=\frac{1}{2}\times base\times height=\frac{1}{2}\times 5\times 1.5=3.75 yd^2

Thus, the area of the trapezoid=A_1+A_2=3+3.75=6.75 yd^2

Thus the first option is the correct option.

4 0
3 years ago
What is the distance of segment BF (look closely...it isn't drawn)?
Vlad [161]
The distance of BF is 7.07
4 0
2 years ago
Solve the polynomial inequation and graph the solution set on a number line. Express the solution in interval notation.
kirill [66]
Solving a polynomial inequation

Solving the following inequation:

(x - 8) (x + 1) > 0

We are going to find the sign both parts of the multiplication,

(x - 8) and (x + 1), have when

x < - 8

-8 < x < 1

1 < x

Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive

We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1

Then

Answer:B

5 0
1 year ago
Simplify the expression: (19^1/9)^9
andrey2020 [161]
(19^1/9)^9=

19^1/9•9=

1/9•9=1

your answer would be 19 hope dis helps :)
5 0
3 years ago
Find the perimeter and area of a rectangle with the following length and breadth:
Vikentia [17]

Answer:

perimeter: 2(l+b) , area : multiply by breadth

Step-by-step explanation:

perimeter: 2(10.5+5.5)

               :206.5m ans

area: 10.5multiply bye 5.5

      :57.75m ans

2: perimeter: 2(15+6.8)

                   : 36.8cm ans

area : 15 multiply by 6.8

        : 102cm ans  

5 0
2 years ago
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